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The answer is 66 feet, 9 inches. Home, first, and second base form a right triangle with legs of 90 feet each. Using the Pythagorean theorem, it is simple to determine that the distance from home to second is 127 feet, 3 inches (rounding off to the nearest inch). Subtract 60'6" (the distance from home to the rubber), which leaves 66'9" as the difference, and thus the distance from second to the rubber.

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Q: What is the distance from second base to the pitchers rubber?
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