In a legitimate ball the maximum number of runs that can theoretically be scored is infinite subject to sequential overthrows being run.
understanding overthrows is relatively simple, for example a run is taken but the ball misses the stumps and is not fielded which allows the batsmen to scamper through for an additional run (subject to it being fielded deeper in the field) this process can be repeated yielding the previous statement, however is extremely unlikely to happen more than twice.
However a ball can be overthrown and cross the boundary, thus giving the batsman his completed runs + four for the boundary overthrow.
In an illegitimate ball the previous scenarios stand but an additional team run is gained through the no ball/wide.
The maximum scoring shot (without overthrows) for a batsman is 6 for crossing the boundary without bouncing.
Next is 5 for hitting an alien object to the field, such as a wicket keepers helmet positioned behind him.
then 4 for a boundary which bounces, 3, 2 and 1 for completed runs between the wicket.
Ball is not counted
Not out. Only way to get batsman out when a no ball is thrown is run out.
Cricket is an example of one sport where a batsman can be run out. This usually occurs when the wickets (or bails) are struck by the ball when the batsman is out of their crease.
The batsman has to hit the ball with his bat and make the ball run off into the ground. Before the fielding team collects the ball and returns it either to the keeper or the bowler, the two batsmen at the two stumps must exchange their position. The batsman has to reach the runners end and the runner would become the batsman. This is one run.
There is only one way. Player should be run out.
Batsman 1 hits the 1st ball behind the keeper and the ball hits bat pad fielder helmet which is behind the keeper, so batsman 1 gets 5 runs and in the next ball batsman 1 scored another one run. So batsman 1 reached 100 runs and he crossed the pitch. Now 1 ball, 1 run to win and batsman 2 is about to strike. He hits the amazing six which makes him score the century and also team won the match. So in 3 balls both the batsman scored their century without fall of wicket. I hope above is the right answer. Thank u Regards, Karthick Batsman 1 hits the 1st ball to 4 runs in the next ball batsman 1 scored 3 runs but umpire declares one run short now batsman 1 complete his century and batsman 2 is on strike and team needs one run to win Now 1 ball, 1 run to win and batsman 2 is about to strike. He hits the amazing six which makes him score the century and also team won the match. Regards, Sanjit
You can't be stumped off a no-ball, but you can be run out, be out obstructing the field, handled the ball, and hit the ball twice. A batsman can be stumped if he steps out of the crease to take a ball, misses it, and the wicket keeper catches it and removes the bails of the wicket before the batsman or his bat re-enters the crease exception is no bAll.
Why not, if they run for a run in no ball then their strikes are automatically changes. But if they are not running for a run in no ball then no chance of changing strikes.
The batsman has to hit the ball with his bat and make the ball run off into the ground. Before the fielding team collects the ball and returns it either to the keeper or the bowler, the two batsmen at the two stumps must exchange their position. The batsman has to reach the runners end and the runner would become the batsman. This is one run.
byes
No, it is the ball that must come into contact with the bails to be considered a run-out.
No, They can't because as soon as one batsman is out it is dead ball. You cannot get out while the ball is dead.