It's possible. All teams would have to win all home or away games and lose all away or home games.
State plays 8 home games and 4 away games next season. Home South Carolina Pitt 2 D-1AA teams UNC Maryland Clemson Away Florida State Wake Forest Virginia Tech Boston College
As of the 2006-2007 season: Each team in the NHL plays 82 games - 41 at home and 41 on the road. 6 games (3 home, 3 away) are played against each team in the Division (24 games) 4 games (2 home, 2 away) are played against the other teams in the Conference (40 games). 18 games (9 home, 9 away) of the season are interconference games. 3 interconference teams play both a home and away game (In Canada it is always the other Canadian teams, in the USA it rotates every year with the other USA teams). The other 12 interconference teams play only once every season rotating home and away.
Pittsburgh Steelers
In the big east there are only 18 conference games and there are 16 big east teams there are some teams they play twice but most not but it will most likely alternate next year ie pitt @ su
All 30 teams play an equal share of 81 home games and 81 away games.
College football teams are assigned to their various divisions based on the size of the school. Most schools that are known by the general public are filed under Division I, and are the ones shown on television for the most part.
Away 33.3% 42.7%.......... Home 55.9%...................
There 18 teams. Each of them play each other twice (Home and away). So 17 * 2 = 34 Games. (17 because 18 teams and they can't play them selfs)
Yes. A student athlete in football gets four tickets to home and away games to give away to whomever they want.
20 teams - Each home and away => (20 * 19 * 2)/2 = 380
They do not play against each team equally; each team plays 4 times against the members of its division; it plays roughly 3 times against teams in its conference or teams near its city; and it plays two times against teams far away, once at home and once away.