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Q: With 20 players in a single elimination tournament how many games have to be played to declare a winner?

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If you have 20 players in a tournament with single elimination, you will have to play 19 games...

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Assuming that a knock out is a single elimination tournament, where each player/team plays until they lose, there are 38 games. Only one team will not lose.

The amount of players in a poker tournament varies from tournament to tournament. For example the poker games played in Vegas accommodate two to approximately sixteen people.

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19

There would be 21 games.

ItS 21 games

10 games From concerned reader: if I am reading the question correctly, the answer of 10 games submitted is not accurate. However, let me clarify the question first. I believe that we are asking how many games must be played in total to determine one, and only one, winner of the entire tournament. Given that this is the correct interpretation of the question, the correct answer is that 19 games must be played to determine a singular winner of the tournament.

The first international chess tournament was played in 1851 and won by Adolph Anderssen. Prior to that there had been games between players from different countries, but that was the first tournament.

There will be 94 games. If a tournament is single elimination, the number of games will always be one less than the number of teams. This is because all teams must lose one game, except for the champion.