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Q: How far from the pitching rubber to 2nd base?

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I believe it's the same distance as the rubber is to home plate, 60 feet, 6 inches.Ken Fougère

from the front of the pitching rubber to the back of home plate is 60'6"

60 ft

The distance from Home Plate to 2nd base is 127+ feet. This is calculated using Pythagorean Theorem (90x90=8100, x2 = 16200, sq. rt. = 127.279 feet) The distance from Home Plate to pitcher's mound is 60 feet, 6 inches, thus the distance from pitcher's mound to 2nd base is 127.3-60.5 feet or roughly 67 feet.

7U and 10U - 35ft.

90 feet.

35 feet from the the tip of home plate to the front edge of the pitching rubber.

Radius is 8 feet with the center being 18 inches in front of pitching rubber.

usually about 30 or 35 feet(:

60 feet 6 inches, just like the MLB.

60 ft, 6 inches for Major League, 46 Feet for Little League.

The pitching rubber is 60 feet 6 inches from home plate. The number was intended to be 60 feet even, but messy handwriting on the baseball field blueprint was read as "6" instead of "0".

every base is 90 feet away from each other

127' 3 3/8"

60 feet 6 inches from the tip of home plate to the pitching rubber on the mound.

The pitching rubber is 60 feet 6 inches from home plate. it was intened to be 60 feet even but messy handwriting on the blueprint made it 6 instead of 0

The distance for a softball pitching rubber is based on the age and ranges between 35 feet to 43 feet.

Same as it is between all bases, 90 feet.

The distance is 60 feet 6 inches from the back of home plate to the front of the pitcher's rubber.

120 feet if you are running from 2nd base to 3rd to home.

rubber basketballs by far

How far is first base to third base

The distance is measured from the back of home plate to the back corner of 2nd base. The distance is 127 feet 3 3/8 inches.

A good question and let me see if I can remember some basic geometry here. We know that it is 60.5 feet from the pitcher's rubber to home plate. We also know that it is 90 feet from home plate to the pitcher's mound. So using the Pythagoreum Theory, which states that the sum of the squares of the sides of a right triangle (distance between home and rubber, distance between first base and rubber) are equal to the square of the hypotenuse (distance between home and first base). This equasion is a2 + b2 = c2 where a is the distance between home plate and the pitching rubber, b is the distance between the pitching rubber and first base, and c is the distance between home plate and first base. So using the information we already know, we can say that: 60.52 + b2 = 902 next, multiply to find the squares 3660.25 + b2 = 8100 next, subtract the 3660.25 from both sides of the equasion b2 = 4439.75 next, find the square root of 4439.75 b = 66.631449031219484653750691943936 The distance between the pitching rubber and first base is 66.631449031219484653750691943936 feet. -------------------------------- The above answer is incorrect, because it assumes that the pithcer's mound is at the exact center of the diamond, when it is, in fact, closer to home plate than 2nd base. The triangle described above is not in fact right, so the Pythagorean Theorem cannot be used. The below answer is correct. PM to 1st = PM to 3rd = 63.717 feet, Law of Cosines:c^2=(60.5)^2+90^2-2(60.5)(90)(Cos 45 degrees) PM to 2nd = 66.779 Feet, Pythagoreum Theorem and Subtraction: c^2 = 90^2 + 90^2, c minus 60.5

The traditional distance for baseball (age 9 to 12) is 46 feet from the point of home plate to the front of the pitching rubber.