'If a catcher is standing on home plate exactly how far does the catcher have to throw the ball to reach second base?

Answer 1

I'm not sure I'm going to answer you question precisely but I'll give you what I know. Because the Baseball diamond is a 90 foot square, the distance is just over 127 ft 3 inches. It's interesting to note that the that the bases are entirely contained within the 90 foot square. Thus the distance of 127 ft 3 inches is from the back point of the home plate to the farthest corner of 2nd base. For the distance from the front of home plate to the front corner of 2nd base, the shortest distance between the two bases, you would subtract 17 inches, the distance from the back of home plate to the front of home plate and then subtract another 17 inches, the distance from the far corner of 2nd base to the near corner of second base, then the distance is approximately 124 ft 5 inches (34 inches less). Hope that helps.

Answer 2

127 feet, minus whatever is between his feet and the back of the plate.

Answer 3

Approx. 93 feet from the point of the plate to the center of second base.

Answer 4

The distance between Home Plate and Second Base is 127 feet, 3 3/8 inches. Standing 5 feet behind the plate, the catcher would be throwing 132 feet, 3 3/8 inches.

Answer 5

he has to throw 112 feet

Answer 6

135 feet