In accordance with Newton's third law of motion, the reaction force occurs simultaneously with the action force. When one object exerts a force on another object, the second object exerts an equal and opposite force back on the first object in the same instant.
The "reaction" force.
IF you mean there are 2 outs then the answer is no, if the out is a force out then the run doesn't count even if the runner touched home before the ball reached the force out bag.
The action and reaction forces occur at the same time.
No. But this rule does not come into effect until AFTER the force out at first base occurs. In other words, until that force out at first happens, the runner who was on first must advance. But AFTER the force out occurs, the runner who was on first need not do so. If a first baseman steps on first and then immediately fires to second base, the person covering second base must tag out the runner coming towards second base. I've seen twenty-year veterans of MLB forget this -- they take the throw from the first baseman after a force out at first base, step on second base, and then walk away without tagging the runner.
The name often given to the force exerted by the first object on a second object is the action force.
Yes it would still be a force play at 2nd base, since the runner going from 1st to 2nd is required to advance (since the runner going to first, has not been put out yet)
reaction force
applied force
applied force
the reaction force
A triple play. Ex. Man on first and second, ball hit to shortstop, who tags runner going to third, throws to second for force at second, second baseman throws to first for force out at first.