For an overthrown ball that winds up out of play (in the stands or dugout), each runner may advance one base. If an overthrown ball does not go out of play but is kicked out of play or by some other means is put out of play, runners may advance two bases. This very, very rarely occurs but lets say there is a routine ground ball to the shortstop and he makes a poor throw to first base that gets by the first baseman and comes to rest in front of the dugout. The catcher runs over to retrieve the ball and, in his haste, kicks the ball into the dugout. In this case, runners may advance two bases.
Chat with our AI personalities
It depends how far away the ball is from the fielder and how fast the runner is but the usual is 1
Like Martin said, it depends. If the ball is overthrown at first and goes past the fence or into the dugout, the runner will get to advance one base. If he is taking off for second before the ball goes under the fence or into the dugout, he will not get to go to third UNLESS he has already touched second by the time the ball goes out of play.
Now, if the ball is overthrown at first and DOES NOT go out of play, the runner may advance as many as he wants but the fielders can get him out.
If the overthrow causes the ball to go out of play, the runner earns one base. If the ball stays in play after the overthrow, the runner isn't earned anything. As long as the ball is in play, the fielder always has an opportunity to pick up the ball and throw a runner out if the runner tries to advance.
If there is an overthrow from the outfield the runner keeps going until he/she is out or until the pitcher has the ball.