The distance of 90 feet (between home and first) is the distance of the middle of the plate and the middle of first base.
The answer is 66 feet, 9 inches. Home, first, and second base form a right triangle with legs of 90 feet each. Using the Pythagorean theorem, it is simple to determine that the distance from home to second is 127 feet, 3 inches (rounding off to the nearest inch). Subtract 60'6" (the distance from home to the rubber), which leaves 66'9" as the difference, and thus the distance from second to the rubber.
The distance between third and home is 90 feet. First to second, and second to third are also 90 feet each.
99 feet. You can find the distance between home and second on any baseball or softball field by using the following formula: A squared plus B squared equals C squared. A is the distance between home and first base B is the distance between first base and second base C is the distance between home and second base.
about 127 ft from the tip of home to the back of 2nd base
91 ft 11 inches
75 ft.
The distance between first base and second base is 90 feet.
180 feet While this is a technically true answer, it is only true if one measures the base runner's path. The distance from home to second, as a crow flies, is about 128'.
No. It is the exact same distance but it was shorter when they moved the mound back The distance from home to the pitching rubber is 60 feet 6 inches. The distance from the pitching rubber to 2nd base is 66 feet 9 3/8 inches. The total distance from home to second is 127 feet 3 3/8 inches.
Home to second on a diamond with bases 60 feet apart woould be 120 feet
the distance between all the bases in major league baseball is 90 feet. home --> first first--> second second--> third third--> home all are 90 feet apart