Two batsman on 94 runs 2balls remaining and 7runs to win both the batsman made their century and won the match?

Answer 1

OK, I can only see one possible way this could happen:

- First ball, Batsman A on strike (94*), 7 to win - the ball is struck (presumably to somewhere in the outfield) and the batsmen take three runs. However, on one of the runs, one of the batsmen accidentally fails to make his ground, so the umpire calls a short run and that run is disallowed (as per Law 18.4(a)). While the ball is still in play the fielder throws it to the wicket-keeper but overthrows it, and the ball goes to the boundary and so an additional four runs are awarded (as per Law 19.6). Thus, six runs (3 runs - 1 short run + 4 overthrows) are awarded to Batsman A for his century and according to Law 18.12(a), Batsman B would now be on strike.

- Second ball, Batsman B on strike (94*), 1 to win - the ball is struck over the boundary for six. Batsman B scores his century and his team wins the match.

If anyone knows of any other way this can be done, please let me know as I would be very interested to hear your solutions. However, according to the laws of cricket, that is definitely one way to solve the problem.

PS - Just thought I'd correct some of the other suggestions. If the ball hits a helmet on the field, the batting side is awarded five penalty runs which would be added to the scorecard as Extras and not the batsman's score. If the last two balls of the innings were in different overs then Duckworth/Lewis would have to be applied and the target would almost certainly change. Any no-balls would again be added as Extras and would then make it impossible for both batsmen to score centuries.