As a pitcher how many strikeouts did Babe Ruth have?

Answer 1

Babe Ruth had a total of 714 home runs. 708 of those were in the American League: 49 while a member of the Boston Red Sox and 659 as a member of the New York Yankees. In 1935, his final year, Ruth played for the Boston Braves of the National League where he hit six more home runs for a career total of 714. See Related Links below (Baseball-Almanac). This site has many baseball records, including home runs.

Addendum:

At one time in 1969, Babe was credited with 715 home runs. In 1919 while playing for Boston, Babe hit a home run. But the rules in 1919 stated that the game was over when the winning run crossed the plate. When Babe hit the home run, there was a runner on first. At the time, the game was tied so when the runner on first crossed the base, the game was over. Babe was credited with a triple but in 1969 the Special Rules Committee awarded him the home rum (along with 18 others in the same situation). But about 6 months later, the Special Rules Committee reversed themselves regarding the Babe and took away the home run. So Babe Ruth has 714 home runs, but for 6 months in 1969, he had 715.

Answer 2

Once every eight plate appearances in the regular season.

For Babe Ruth's career, he had 10,616 regular season plate appearances and 1,330 regular season strikeouts.

In World Series play, he had 167 plate appearances and 30 strikeouts for an average of one strikeout every 5.6 plate appearances.

Answer 3

Babe Ruth struck out 1,330 times in 8,398 at bats during his career.

Answer 4

From 1914 to 1933, Babe Ruth struck out 488 batters.

480 of those were in a five-year period: 1915 thru 1919.

Answer 5

1082