M+(m+15)=55
or Michael has 20 cards.
51
Bob has 51 cards; Bill has 17.
51. Bob has 3/4 of 68.
You have a total of 50 cards, with 15 being baseball cards. The problem states you have 110 football cards, which exceeds the total number of cards you have, indicating a mistake in the numbers provided. If we assume the remaining cards are all basketball cards, you would need to clarify the total number of football cards to answer how many more basketball cards than baseball cards you have.
nines
M= Marlon J=Jake S= Sam4x4+3MxJ+3=Total
He owns a total of 8 packs (5+3) so at 12 cards each (8 * 12) he owns a total of 96 cards.
This works out fairly simply, He has 8 football cards and 24 Baseball cards.
Inez=2b Shaquille=b Total=2b+b, or 3b
This can be solved algebraically.Set the variable x as the number of cards Bob has.Then express the number of cards that Bill has, in terms of x (Bob's cards).Bob = xBill = only 1/3 as many as BobTheir total is 68.So x + (1/3 x) = 684/3 x = 68Multiply both sides by 3.4x = 204and x =51 and 1/3 x = 17So Bob has 51 cards and Bill has a third as many, or 17, for a total of 68.
Michael has 20 CDs
Michael has 20 CDs