M+(m+15)=55
or Michael has 20 cards.
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51
Bob has 51 cards; Bill has 17.
51. Bob has 3/4 of 68.
nines
M= Marlon J=Jake S= Sam4x4+3MxJ+3=Total
He owns a total of 8 packs (5+3) so at 12 cards each (8 * 12) he owns a total of 96 cards.
This works out fairly simply, He has 8 football cards and 24 Baseball cards.
Inez=2b Shaquille=b Total=2b+b, or 3b
This can be solved algebraically.Set the variable x as the number of cards Bob has.Then express the number of cards that Bill has, in terms of x (Bob's cards).Bob = xBill = only 1/3 as many as BobTheir total is 68.So x + (1/3 x) = 684/3 x = 68Multiply both sides by 3.4x = 204and x =51 and 1/3 x = 17So Bob has 51 cards and Bill has a third as many, or 17, for a total of 68.
Michael has 20 CDs
Michael has 20 CDs
There were a total of 17 red cards and a total of 260 yellow cards. making a total of 277 cards in all.