51
51. Bob has 3/4 of 68.
24
This works out fairly simply, He has 8 football cards and 24 Baseball cards.
13 yellow cards and 16 red cards all together 29 cards
The probability of drawing three diamonds from a standard deck of 52 cards is (13 in 52) times (12 in 51) times (11 in 50), or 1716 in 132600, or about 0.01294.
2
This can be solved algebraically.Set the variable x as the number of cards Bob has.Then express the number of cards that Bill has, in terms of x (Bob's cards).Bob = xBill = only 1/3 as many as BobTheir total is 68.So x + (1/3 x) = 684/3 x = 68Multiply both sides by 3.4x = 204and x =51 and 1/3 x = 17So Bob has 51 cards and Bill has a third as many, or 17, for a total of 68.
The probability of drawing three queens from a deck of cards is (4 in 52) times (3 in 51) times (2 in 50), or 24 in 132,600 or 1 in 5,525.
Exactly four-and-twenty times as much as the worth of one cereal baseball card, one would normally suppose. But, as I have none, I suppose that, if I gathered up all my baseball cards, they would have a combined value of naught. By the bye, how much are your baseball cards worth?
Click your heels together three times and say "Bubbanush!"
I'd say roughly three times as I've seen lots of duelists do