nope, as long as you get the out no runs count.
The runner on second base can be thrown out provided that first base is empty
If there are less than two outs, yes. If there are two outs, this is a timing play. If the runner crosses home plate before the batter is thrown out at second base, the run counts. If the batter is thrown out at second base before the runner crosses home plate, the run does not count.
It is a base hit once the batter-baserunner passes first base. This will not change by being thrown out at second.
If the runner at second is out by being forced out, the batter is not given a base hit .... the play is ruled the same as if the ball was hit to an infielder that threw to second to force the runner. If the runner at second is out by being tagged because they rounded the base too far, the batter is given a base hit.
That would depend on whether the runner that made the base running error was forced out. If there is a runner on first base and the batter hits a ground ball into left field and the runner trips and falls between first and second and the left fielder throws to second and gets the runner out, it would be considered a force out and the batter would not get credited with a hit. But if there is a runner on first base and the batter hits a ground ball into left field and the runner rounds second base too far and the left fielder throws to second and the runner is tagged out, the batter would be credited with a base hit.Answer:The above is incorrect. In order for the batter to receive a Fielder's Choice and not be credited with the hit, the scorer must determine that the batter would not have safely reached 1st base. In simple terms: "the fielder COULD have thrown out the batter, but CHOSE not to". In the example above, the left fielder could not have thrown out the batter at first. The batter is awarded the hit and the defense records a 7-4 put out.A force out does not determine a Fielder's choice. If there is a runner on 2nd with 1st empty: If the batter hits a sharp ground ball to second basemen who fields the ball cleanly and attempts to throw out the runner advancing from 2nd, the batter is given the fielder's choice whether the advancing runner is safe or out at 3rd.
No, because the third out was made on the same play. It is no different than if the batter hits a ground ball to the shortstop or any other infielder and is thrown out at first base for the third out. However, if there are two outs and there is a runner on third and the batter hits a single into left field but is thrown out at second when attempting to turn the play into a double and the runner on third makes it home before the third out at second is recorded, the run does count. Hope that isn't too confusing.
No. After ball four is thrown to the batter it is a base on balls. The batter is entitled to first base, and any base runner forced ahead may advance. Even if the runner on first is attempting to steal on the pitch, he is awarded second base and cannot be thrown out. Of course the runner from first is award second base, but is only protected up to the base. If he overruns or overslides the second base because in his steal attempt he was not paying attention, he can be tagged out if he is off the bag.
If the runner who started on 3rd base is the one thrown out at home, no it is not a hit. It is ruled a fielder's choice
The runner isn't awarded anything. If the fielder can get the ball in time, the runner can still be thrown out at second. The runner is only awarded if the ball is thrown out of the playing field, such as the dugout or the stands. It is then declared a dead ball and is treated like a ground-rule double; The runner receives his extra base.
Provided that there were no runner on 1st base and batter reached 1st before runner were tagged out, this is a hit. Batter alreay had first base, runner chose to go to 3rd, not forced. If he were forced, then it is a fielders choice.
Yes, as long as the batter thrown out at first is not the third out of the inning.