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Q: How many feet between the pitchers mound and first base?

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150 feet I'm sorry but the answer above is incorrect. the full distance between 3rd and 1st is only 127.28 feet. The distance from 1st to the pitchers mound is 63.72 feet. the same goes for 3rd to pitchers mound.

The distance between first and third base is 127.28 feet. Some people think that you can just divide that by 2 to get the distance between the mound and first or third base, but the pitcher's mound does not touch the straight line between first and third. It is actually lower, so the actual distance between first (or third) and the middle of the pitchers mound is 63.72 feet. This is according to the diagram on page 4 of the Official Baseball Rules (2011 edition)

It is a little over 110 degrees

Yes

The pitchers mound

5 First base Second base Third base Home Pitchers mound

pitchers mound first base second base third base home plate outfield dugout

45' to 35' feet

63.717 feet

it is 90ft from base to base. 60ft from pitchers mound to home base. the outfeild varys from feild to feild.

If a batted ball strikes the mound and then ricochets into foul territory, before reaching first base or third base, and it isn't touched by a fielder, then it is foul.

the distances between 1st, 2nd, 3ed, and home plate are 60 feet and from home plate to the pitchers mound is 40 feet. this depends on the league you play in and what level softball.

The distance between the pitcher's mound to the baseball diamond is roughly 60.5 ft. The distance from homeplate to first base is around 90ft. So basically, the homeplate portion of the baseball diamond is 90 degrees. So if you break that in half that's roughly 45 degrees. Then using law of cosine and using the variable C in place of the distance between the pitcher's mound to first base, you get c^2=(60.5)^2+90^2-2(60.5)(90)(Cos 45) which turns out to be c^2=4059.86. Square that and C= roughly 63.717 and that is the distance between the pitcher's mound to first base. The distance between the pitcher's mound and home plate is exactly, not roughly, 60.5 feet. Another respondent asked why it is not a simple 45-45-90 triangle, and the answer to that is because the pitcher's mound is NOT located in the exact center of the diamond. The pitcher's mound is closer to home plate than it is to second base.

89 feet from the back tip of home plate

I'm assuming you mean USA baseball. The distance between home plate and the pitcher's rubber (the center of the mound) is 60 feet 6 inches. The distance between each base around the diamond is 90 feet.

From home plate to second base is about 127ft, and the distance from home plate to the pitcher's mound is 60ft, so it's about 67ft from the pitcher's mound to second base. More precisely, it is 127ft 3 3/8" home to second and 60ft 6" mound to plate.

The distance from the pitchers mound to home plate is 60'6'. The distance between all the bases is 90 feet. the home plate area is in a 26' circle. The distance between home and second base is 127' 3 3/8'. That's also the dimension from first to third base.

180 feet ,that's going from 1st base to 2nd base to 3rd base. in the MLB. LIKE IF YOU HIT A TRIPLE but not sure what the direct angle if you just went from 1st base over the pitchers mound to 3rd base. I think its 127 feet.3 inches

The dimensions of a major league baseball diamond are 90 feet from base to base. The distance from home plate to the pitchers mound is 60 feet and 6 inches.

Yes, there used to not be any set distance at all No, the distance between bases has not changed since major league baseball began in 1876. The distance between home plate and the pitchers mound changed several times before it settled at 60'6" in 1893.

home plate to the mound would be 18.47 meters ...first - second would be 27.43 meters ...center field would be 125.88 meters ...

Good question and to find out the answer let me go back and try to remember some elementary geometry. If a straight line is drawn from home plate to the pitcher's rubber on the pitching mound that line would measure 60.5 feet. If a straight line is drawn from home plate to first base that line would measure 90 feet. If a straight line is drawn from the pitcher's rubber to first base that line would measure X feet. If I remember the Pythagorean Theory correctly, the square of the hypotenuse of a right triangle (distance from home plate to first base), is equal to the squares of the distance of the other two sides of the right triangle added together (distance from the pitcher's rubber to first base, and distance from the pitcher's rubber to home plate). This equation would read as: 60.52 + X2 = 902 ------ next do the multiplication to find the squares 3660.25 + X2 = 8100 ----- next find the value of X2 by subtracting 3660.25 from 8100. X2 = 4439.75 ----- next find the square root of 4439.75 X = 66.631449031219484653750691943936 Therefore, the distance between the rubber on the pitcher's mound and first base is 66.631449031219484653750691943936 feet. That is not the correct answer. This answer improperly assumes that if you form a triangle with home plate, first base and the pitchers mound you have a right triangle, that is a triangle with a 90 degree angle between at the pitchers mound. That is incorrect. The correct answer is 63.716 feet and it is found as follows: The distance between home plate and second base is equal to: the square root of 902 + 902 (the distance between home plate and first and between first and second bases) = 16,200, the square root of which is 127.2792 feet, which also the straight line distance between first base and third base. If you draw a straight line between 1st and 3rd and also between home and second those lines will intersect halfway between home and second which is 63.6396 feet from home plate or 3.1396 feet behind the pitchers rubber. The distance of this intersection from first base is also 63.6396 feet. If you draw another straight line between the pitchers rubber and first base you have a new right angle triangle that is formed by the line from the line from the rubber to first base (which is the hypotenuse), the segment on the line from home to second between the rubber and the intersection of the lines between first and third and home and second (which is 3.1396 feet) and the line segment from first base to third where it intersects with the line from home to second which is also 63.6396 feet. Now you have a right triangle to which the Pythagorean Theory can be applied. The distance between the rubber and first base will be the square root of the sum of 3.13962 + 63.63962. The sum of 3.13962 + 63.63962 = 4,059.8558, the square root of which is 63.7169975 feet. While the above answer is close, the correct answer is 63.7169975 feet which is 3 feet shorter than the wrong answer.

9 player on the field The catcher is the player squating down behind home plate. On the pitchers mound is the pitcher who throws pitches. Nearest to first base is the first baseman. Between first and second base is the seccond baseman. Between second base and third base is the shortstop. Nearest to third base is the third baseman. In the center of the outfield is the center fielder. On the left side of the outfield from the batters perspective is the left fielder. On the right side of the outfield from the batters perspective is the right fielder.

This is because the rules of baseball say the mound is a distance from homeplate that is less than halfway the distance between homeplate and 2nd base. The distance is the same between each base in order (the same from home to 1st, 1st to 2nd, 2nd to 3rd, 3rd to home.) This results in the distance between homeplate and 2nd equal to the distance between 1st and 3rd. If you draw a line between homeplate and 2nd, and a line between 1st and 3rd, the lines will intersect in the center of the baseball diamond. However, the center point will be behind the pitcher's mound. You can use the Pythagorean Theorem to prove the distance from the mound to home is less than the center point, but that is another question. (Hint: The distance squared from home to first plus the distance squared from first to second divided by 2).

The DH then proceeds to first base.