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In a regular MLB game, it is about 60 feet. Normally it should be the same distance from the pitcher's mound to home plate.

Q: How many feet between the pitchers mound and first base?

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It is a little over 110 degrees

5 First base Second base Third base Home Pitchers mound

The pitchers mound

45' to 35' feet

There is a pitcher's circle but no actual mound of dirt. There is a pitcher's circle but no actual mound of dirt.

I'm assuming you mean USA baseball. The distance between home plate and the pitcher's rubber (the center of the mound) is 60 feet 6 inches. The distance between each base around the diamond is 90 feet.

The Mets' dugout at Citi Field is on the first base side.

150 feet I'm sorry but the answer above is incorrect. the full distance between 3rd and 1st is only 127.28 feet. The distance from 1st to the pitchers mound is 63.72 feet. the same goes for 3rd to pitchers mound.

Yes, there used to not be any set distance at all No, the distance between bases has not changed since major league baseball began in 1876. The distance between home plate and the pitchers mound changed several times before it settled at 60'6" in 1893.

This is because the rules of baseball say the mound is a distance from homeplate that is less than halfway the distance between homeplate and 2nd base. The distance is the same between each base in order (the same from home to 1st, 1st to 2nd, 2nd to 3rd, 3rd to home.) This results in the distance between homeplate and 2nd equal to the distance between 1st and 3rd. If you draw a line between homeplate and 2nd, and a line between 1st and 3rd, the lines will intersect in the center of the baseball diamond. However, the center point will be behind the pitcher's mound. You can use the Pythagorean Theorem to prove the distance from the mound to home is less than the center point, but that is another question. (Hint: The distance squared from home to first plus the distance squared from first to second divided by 2).

The distance between the pitcher's mound to the baseball diamond is roughly 60.5 ft. The distance from homeplate to first base is around 90ft. So basically, the homeplate portion of the baseball diamond is 90 degrees. So if you break that in half that's roughly 45 degrees. Then using law of cosine and using the variable C in place of the distance between the pitcher's mound to first base, you get c^2=(60.5)^2+90^2-2(60.5)(90)(Cos 45) which turns out to be c^2=4059.86. Square that and C= roughly 63.717 and that is the distance between the pitcher's mound to first base. The distance between the pitcher's mound and home plate is exactly, not roughly, 60.5 feet. Another respondent asked why it is not a simple 45-45-90 triangle, and the answer to that is because the pitcher's mound is NOT located in the exact center of the diamond. The pitcher's mound is closer to home plate than it is to second base.

A batted ball that hits the pitcher's mound (or any base) is considered a fair ball. A fair ball that lands out of play is considered a ground rule double.