beats me
Bob has 51 cards; Bill has 17.
51
51. Bob has 3/4 of 68.
45 cards
28.
24
This can be solved algebraically.Set the variable x as the number of cards Bob has.Then express the number of cards that Bill has, in terms of x (Bob's cards).Bob = xBill = only 1/3 as many as BobTheir total is 68.So x + (1/3 x) = 684/3 x = 68Multiply both sides by 3.4x = 204and x =51 and 1/3 x = 17So Bob has 51 cards and Bill has a third as many, or 17, for a total of 68.
You will have 66 baseball cards and 86 soccer cards.
You start backwards, you know you have 80 baseball so that makes 40 football. 20 basketball, and 40 hockey.
This works out fairly simply, He has 8 football cards and 24 Baseball cards.
How many world series have the St. Louis Cards won
M= Marlon J=Jake S= Sam4x4+3MxJ+3=Total