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How do you calculate distance from home plate to second base as if you were the catcher throwing the ball to second base from home?
Wiki User
∙ 12y ago
Pythagorean principle on a right triangle: A2 plus B2 = C2 with A and B being adjacent sides of triangle. A and B are both 90. So, 90-squared =8100.
Two times 8100 =16200. Square root of 16200 = 127.279.
Wiki User
∙ 12y ago
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The distance from home plate to first base is 90 feet and the distance from first base to second base is also 90 feet making a right angle; you can calculate how far the catcher needs to throw to 2nd base from home by Pythagorean theorem. Answer is 127.3 feet
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