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If a 70-kg swimmer pushes off a pool wall with the force of 250N at which rate will the swimmer accelerate from the wall?
56
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How do you find what percent 40 would be of 250?
40:250::n:100% 250n = 4000% n = 16%
What are the theoretical mechanical advantages of the 3 different types of levers?
In first-class levers, the fulcrum is located between the effort force and the resistance force, providing a mechanical advantage that can increase force or distance. In second-class levers, the resistance force is between the fulcrum and the effort force, allowing for a greater mechanical advantage in terms of force but not distance. In third-class levers, the effort force is applied between the fulcrum and the resistance force, offering a mechanical advantage in terms of distance but not force.
A skydiver who weighs 500 N reaches terminal velocity of 90kmh the air resistance on the diver is then?
The air resistance on the skydiver at terminal velocity is 500 N. At terminal velocity, the air resistance on the skydiver is equal in magnitude to the gravitational force pulling them downward. This balance of forces results in a constant velocity.
What states are on 25N latitude?
250N Latitude passes just south of Brownsville TX in Mexico,) and through south Florida slightly north of Key West.
40kg rolled up a 10meters long rampHow much does the barrel weight and if a person excerted a focre of 250N to roll along the ramp what was the efficiency of the ramp?
And the question is????
David weighs 250n and Jane weighs 300n they sit 2m from the pivot of a seesaw how far away does their mother have to sit if she weighs 500n?
The total torque on a seesaw must be balanced, so we can use the equation (David's weight * David's distance) = (Mother's weight * Mother's distance). Solving for Mother's distance, we get: (250N * 2m) = (500N * Mother's distance). Thus, the mother should sit 1 meter away from the pivot.
How many lbs are in 250 newtons?
To convert newtons to pounds, you can use the conversion factor: 1 Newton is approximately equal to 0.224809 pounds. Therefore, 250 newtons is approximately equal to 56.2 pounds.
Pulley system is used to lift 2000 newton and a distance of 3 meters the operator must apply a force of 250 N and to lift engine 3 meters the operator must pull a total 30 metersWhat is the value of w?
To find the weight of the engine (w), we can use the formula: work done = force × distance. In this case, the work done lifting the engine is the same whether the distance is lifted in one go or 30 small steps. Therefore, 250N × 3m = 30 steps × w × 3m. Solving for w gives w = 250 N.
If The force of gravity on the moon is approximately one sixth that of the earth The direct variation formula for weight on the earth compared to weight on the moon would be?
The direct variation formula for weight on Earth compared to weight on the Moon is: weight on Earth = 6 * weight on the Moon. This formula shows that the weight on Earth is 6 times greater than the weight on the Moon due to the difference in gravitational force between the two celestial bodies.
What would be the force required to stop a car of mass 100kg and a loaded truck of mass 10000kg in 2s if they were moving with the same velocity of 5 m per S?
The force required to stop an object is given by the formula F = ma, where m is the mass and a is the acceleration. The acceleration needed to stop the car and truck in 2 seconds while moving at 5 m/s is 2.5 m/s^2. Therefore, the force required to stop the car is 250 N and the force required to stop the truck is 25000 N.
The weight of the body on the surface of the is 250N. calculate its weight at distance equal to half of radius of the earth below the surface of earth. (radius of earth6400km)?
The weight of the body is determined by the universal law of gravitation, which states that the force is inversely proportional to the square of the distance between the centers of the two objects. Therefore, at a distance equal to half the radius of the Earth below the surface, the weight of the body would decrease because the distance from the center of the Earth has increased, resulting in less gravitational force. To calculate the weight at this new distance, the inverse square law can be applied by considering the new distance from the center of the Earth.
