How many gallons are in an 16 by 32 with the shallow end being 3ft deep and the deep end being 9ft deep?

Answer 1

Here's a formula for round pools:

distance across*distance across*depth*5.9

for rectangles:

length*width*depth*7.5

or for a deep end:

length*width*((shallow end depth + deep end depth)/2)*7.5

so in your case, 16*32*(3+7)/2*7.5=20000 gallons

Answer 2

Assuming that the angle is straight from shallow to deep end

Breaking the problem into the cube part for the top half:

20x40*3.5=2800 Ft^3

Add in the pyramid for the bottom part:

(first, need the length of along the bottom):

A^2+B^2=C^2

40ft^2+5.5^2=40.5ft bottom length

V = (1/2)b*h*l

.5*40.5*5.5*40 = 4455 Ft^3

Top Cube + Bottom Prism = Total volume in Cubic Feet

2800 + 4455 = 7255 Ft^3

1 US Gallon = 0.133680556 Cubic Feet

7255/0.13368 = 54271 Gallons

Answer 3

I just need to know in order to convert to a salt pump in a few months...

Answer 4

The pool has a capacity of 2176 cubic feet.

Approximately 7.48 gallons is equivalent to 1 cubic foot.

Therefore the pool has a capacity of approximately 16 276 gallons.

Answer 5

If the pool starts at 4 feet deep and ends at 6 feet deep in a constant slope along its entire length with no "shelf," then the answer is 119,150 gallons.

Answer 6

Assuming the change in depth is along the 32 foot length, the slope is at a constant angle and it were filled to the brim it would hold 21065 US gallons of water.

Answer 7

28,723.2 gallons

Answer 8

just under 40,000 gallons