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Assuming that the angle is straight from shallow to deep end

Breaking the problem into the cube part for the top half:

20x40*3.5=2800 Ft^3

Add in the pyramid for the bottom part:

(first, need the length of along the bottom):

A^2+B^2=C^2

40ft^2+5.5^2=40.5ft bottom length

V = (1/2)b*h*l

.5*40.5*5.5*40 = 4455 Ft^3

Top Cube + Bottom Prism = Total volume in Cubic Feet

2800 + 4455 = 7255 Ft^3

1 US Gallon = 0.133680556 Cubic Feet

7255/0.13368 = 54271 Gallons

Q: How many gallons are in an 16 by 32 with the shallow end being 3ft deep and the deep end being 9ft deep?

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An in-ground pool that is 40 feet by 20 feet with the shallow end being 3ft deep and the deep end being 9ft deep has a volume of approximately 35,900 US gallons. (The depth of variable depth pools is generally calculated by adding the shallow and deep ends and dividing by two).

Not enough information. need length and width

25000 gallons

Cannot be answered without knowing the shallow and deep end depths.

24,685.79 gallons

20000

If the pool is 8 feet in the deep end and 3 feet in the shallow end, the total volume will be about 21,722 gallons of water.

If the pool is 8 feet in the deep end and 3 feet in the shallow end, the total volume will be about 38,507 gallons of water.

14,949 gallons. 4,147,200 in^3, with 0.00360464866 gallons per in^3.

18,691.2 gallons if shallow end 4'

10000000 gallons of water ;) it's true, my teacher told me

10,710. 10,710. The calculation for a rectangle pool is: ((Shallow end depth + deep end depth) / 2) * length * width) = pool volume in cubic feet Pool cubic feet * 7.5 = gallons of water the pool holds