To calculate this, you divide the change in velocity, by the time.
the magnitude of the skydivers acceleration is zero as he is decelerating by opening his parachute!
80 m/s2 up
66.7 m/s2
Only if they have a heart attack, but not likely.
80 m/s 2 up
When a skydiver opens their parachute, air resistance increases which slows down the skydiver. Terminal velocity is the maximum speed a falling object can reach when the force of gravity is balanced by the force of air resistance. Opening the parachute decreases the skydiver's speed, allowing them to land safely.
Maximum speed is about 220 to 230mph and can be achieved after about 20 seconds of freefall. Normal parachute opening speed should be not greater that 120mph to avoid damage to the parachute
If the 0.75 refers to seconds, then his acceleration is -66.66... (repeating) metres per second^2.
-- The force of gravity is unchanged before and after.-- The force of air resistance on the skydiver is greater before, and less after,because she is falling slower after the parachute opens.-- The effect on her of air resistance is greater after the parachute is open. Theincreased air resistance itself acts on the parachute, and its effect is transferredto the skydiver through her harness.
He will decelerate (meaning an acceleration in the direction opposite of current velocity) at a rate of (54 m/s - 4 m/s)/.75 seconds = 66.67 m/s2. This is about 6.8 Gs.
(4 m/s - 54 m/s)/0.75 s = -50/0.75 m/s² = -200/3 ≈ - 66.67 m/s² (negative because he is decelerating)
A skydiver falls with a constant speed, known as terminal velocity, after opening their parachute because the force of gravity pulling them down is balanced by the drag force from the air resistance acting against their fall. Once the parachute is deployed, it increases the surface area, significantly enhancing air resistance. When these two forces equalize, the skydiver stops accelerating and descends at a steady speed. This balance between gravitational force and air resistance is what stabilizes the descent.