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To ensure you have at least one ball of every color, you need to consider the worst-case scenario. If there are ( n ) different colors, you could potentially draw all the balls of ( n-1 ) colors before finally drawing a ball of the last color. Therefore, the minimum number of balls you need to draw to guarantee that you have at least one ball of each color is ( n + (n - 1) = 2n - 1 ).

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5mo ago

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