1 Login to gain access to Desktop User Environment
2 Click Start Menu Button
3 Click the Run Option
4 Type cmd in the available box
5 Once the Command prompt is displayed type the ping command with a space then the PC host name or IP Address
6 Press Enter to Execute the Ping
7 Verify the Results for Echo Replies that Validates Communications
1. Login to gain access to Desktop User Environment 2. Click Start Menu Button 3. Click the Run Option 4. Type cmd in the available box 5. Once the Command prompt is displayed type the ping command with a space then the PC host name or IP Address 6. Press Enter to Execute the Ping 7. Verify the Results for Echo Replies that Validates Communications
a system that allows direct communications between user and computer - 2 misses
Skippy - 1967 The Perfect Hosts 2-2 is rated/received certificates of: Australia:G
In MikroTik RouterOS, Layer-3 communication between two hosts can be achieved using an address subnet of at least a /30 (255.255.255.252) for point-to-point links or larger subnets like /24 (255.255.255.0) for networks with multiple hosts. Each host must have a unique IP address within the same subnet, and they must be correctly configured with the appropriate gateway settings. Proper routing must also be established to facilitate communication between the hosts.
In Class A networks, the maximum number of hosts is calculated as (2^{24} - 2), which equals 16,777,214 hosts. This formula accounts for the network and broadcast addresses, which cannot be assigned to hosts. Class A networks use the first octet for the network identifier, allowing for a large number of hosts within a single network. However, not every Class A network will have the maximum number of hosts; it depends on the specific subnetting used.
class A ip has 16777216 host but valid hosts are only 16777214.(2^24-2)So answer is 16777214 hosts
A subnet mask of 255.255.255.248 corresponds to a /29 prefix, which means there are 3 bits available for host addresses (since 32 bits total - 29 bits for the network = 3 bits for hosts). The formula for calculating the number of addressable hosts is 2^n - 2, where n is the number of host bits. Thus, 2^3 - 2 equals 6 addressable hosts on this network.
Lingo - 2002 GSN Hosts Edition 2-59 was released on: USA: 1 April 2003
one for broadcast i.e 256 and anthoer one is network i.e 0(zero)
Sergio catalan lorena herra
Morning Drive - 2011 Ryan Burr Hosts 2-180 was released on: USA: 30 August 2012
yes like 2