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No, and there would be no need for a tiebreaker in this situation. The team with a 9-7 record has more victories and therefore is ranked higher than a team with an 8-6-2 record.

The first is wrong. In the NFL, ties are statistically counted as half a game won, half a game lost. Therefore, 8-6-2 is exactly the same, in terms of winning percentage, as 9-7.

The 8-6-2 team would thus not win a tiebreaker by virtue of its record alone, but neither would the 9-7 team. The teams would be considered to have equal records, and the usual NFL tiebreakers would go into effect to determine divisional standings, playoff seedings, and so on.

Q: Will an NFL team with a 8-6-2 record win a tiebreaker over a team with a 9-7 record?

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837 over 2155334.8 over 862 times 103348 over 8620divide 21674 over 4310divide 2837 over 2155that's the steps

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It is: 862 = DCCCLXII

862

1, 2, 431, 862

862+288=1150

862 + 137 = 999

862 is an even number.

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BCD of 862 is 100001100010

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