Q: What is a Louisville Slugger 125 Y bat?

Write your answer...

Submit

Still have questions?

Related questions

The "125" refers to the grade of wood used to make the bat. "125" is the highest grade and is reserved for all pro level bats. The "125" bats are also used for the highest quality store model bats.The 125 is not the Model number. Louisville slugger began using model numbers on the knob in 1943 then moving the model number to the barrel in 1977.Flame Tempered is a process of drying and hardening the wood with lower grade baseball bats. If your bat reads "Flame tempered it is a store model bat. "Powerized" is used on higher grade bats, and professional models. "Bone Rubbed"the same process for hardening the wood appears on bats made in the 1920s

125% * y = 100 1.25y = 100 y = 80.

Y^2 = 125 Y = +/- sqrt(125) Y = +/- 5sqrt(5)

y = 125 - x

what is the word problem that can be evaluated fby the algebraic expression y-95 and evaluaate it for y=125

y varies directly as x so y = cx for some constant c. y = 125 when x = 25 so 125 = c*25 so that c = 5 ie the relationship is y = 5x Then when x = 2, y = c*x = 5*2 = 10

La Revilla y Ahedo's population is 125.

Given x=k1y and x=k2/z x=125 ,y=5 then k1=25 x=125 , z=4 then k2=125(4)=500 If y=4 ,z=5 then x=25y = 100

The syllables for battery are: bat-ter-y.

67 adult ticket 58 student tickets total cost $413 total tickets 125 just set up a set of simultaneous equations such as if number of adult tickets is x and number of student tickets is y x+y=125 since 125 tickets are being bought then multiply amount of tickets by ticket cost 4x+2.5y=413 both equations are true so the easiest way to solve it is by solving the first equation first by saying x=125-y plug this new value of x into the second equation by replacing x 4(125-y) +2.5y=413 solve this equation for y then plug the value of y back into x=125-y to find the value for x

he didnt have a bat robe

With the equation of an ellipse in the form (x/a)² + (y/b)² = 1 the axes of the ellipse lie on the x and y axes and the foci are √(a² - b²) along the x axis. 9x² + 25y² + 100y - 125 = 0 → (3x)² + 25(y² + 4y + 4 - 4) = 125 → (3x)² +25(y + 2)² - 100 = 125 → (3x)² +25(y + 2)² = 225 → (3x)²/225 + (y + 2)²/9 = 1 → (x/5)² + ((y+2)/3)² = 1 Thus the foci are √(5² - 3²) = √16 = 4 either side of the y-axis, but the y axis has been shifted up by 2, thus the two foci are (-4, -2) and (4, -2).