This is slang in paintball for the "snake" bunkers. S1 is the first part of the set of bunkers and S2 is usually towards the middle of the field. Players commonly yell this out to let the rest of the team to let them know where the players are.
gennerally the number refers to the "knuckles" or divisions in the snake rather than a half way point, so s1 is the first knuckle, meaning there is a player behind that, and s2 is the second etc, there can be many knuckles in a snake
D is often for Doritos (the triangular bunkers)
and C is a Can (large cylindrical bunkers) beyond those people will usually call out the names
Statement S2 is anti-dependent on statement S1 if S2 follows S1 in program order and if the output of S2 overlaps the input of S1. The anti-dependence S1 to S2 define as cross arrow such as S1 |-> S2.
strlen(s1) to find the length of the string s1 strcpy(s1,s2) copy source string to destination string(i.e copies s2 to s1,s2 remain unchanged) strcmp(s1,s2) compares s1 and s2 and prints 0 if s1 and s2 are equal,-1 if s2 is greater, 1 if s1 is greater strcat(s1,s2) combines string s1 and s2 to a single word and stores it in s1 strupr() converts lower case string to upper case strlwr() converts upper case string to lower case
Definition: A set S1 is a superset of another set S2 if every element in S2 is in S1. S1 may have elements which are not in S2.
It cannot be proven because it is not true. Suppose S1 = {0,1,2,3} and S2 = {0,5,10} then S1 u S2 = {0,1,2,3,5,10} then |S1| = n = 4, |S2| = m = 3 but |S1 u S2| = 6 which is NOT n+m = 7
Area = square root of {s1(s1-a)(s1-b)(s1-p)} + square root of {s2(s2-c)(s2-d)(s2-p)} where a,b,c and d are the four sides of the quadrilateral, p is the diagonal separating the sides a,b from c,d, and s1 = (a+b+p)/2 and s2 = (c+d+p)/2
t1 s1 b1 t1 s1 b2 t1 s2 b1 t1 s2 b2 t2 s1 b1 t2 s1 b2 t2 s2 b1 t2 s2 b2 t3 s1 b1 t3 s1 b2 t3 s2 b1 t3 s2 b2 TOTAL 12 combinations OR 2(3 x 2) = 12
s1 : Continiuos running
let s1,s2,s3 be three sides of a triangle.import java.lang.*;import java.io.*;import java.util.*;class Triangle{public static void main(String args[]){boolean test=false;int s1,s2,s3;Scanner input = new Scanner(System.in);System.out.println("enter the side1 of triangle");s1=input.nextInt();System.out.println("enter the side2 of triangle");s2=input.nextInt();System.out.println("enter the side3 of triangle");s3=input.nextInt();if((s1*s1)==(s2*s2)+(s3*s3)){test=true;}else if((s2*s2)==(s1*s1)+(s3*s3)){test=true;}else if((s3*s3)==(s1*s1)+(s2*s2)){test=true;}if(test==true)System.out.println("Entered sides form a right angle triangle.....");elseSystem.out.println("Entered sides dosn't form a right angle triangle.....");}}
char *strmerge (char *s3, const char *s1, const char *s2) { strcpy (s3, s1); strcat (s3, s2); return s3; }
unsigned char * memcpy(unsigned char * s1, unsigned char * s2, long size) { long ix; s1= (char *)malloc(sizeof(strlen(s2))); for(ix=0; ix < size; ix++) s1[ix] = s2[ix]; return s1; }
it is school years in Scotland
partition coefficient = [s1] / [s2] [s1] is conc of drugs in phase 1 and [s2] is conc of drugs in phase 2.