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I believe the tiebreaker is calculated in the following manner. Sort all 32 teams (16 if only interested in the conference) by points scored. Assign a point scored rank of 1 to the highest scoring team, 2 to the next highest, etc. Repeat the procedure for points allowed. Then add the "points scored rank" to the "points allowed rank" to get the combined ranking. The lowest number wins the tiebreak. For example, the best combined rank is 2 (first in points scored + first in points allowed). Similarly, the worst combined rank is 64 (assuming 32 teams in the league). This link shows the rankings for 2006: http://www.nfl.com/stats/categorystats?archive=false&conference=null&role=TM&offensiveStatisticCategory=SCORING&defensiveStatisticCategory=null&season=2006&seasonType=REG&tabSeq=2&qualified=true&Submit=Find Points Scored Ranks, 2006 Rk Team Points

1 San Diego Chargers 492

2 Chicago Bears 427

2 Indianapolis Colts 427

4 Dallas Cowboys 425

5 New Orleans Saints 413

Points Allowed Ranks, 2006 Rk Team Points

1 Baltimore Ravens 201

2 New England Patriots 237

3 Chicago Bears 255

4 Jacksonville Jaguars 274

5 Miami Dolphins 283 So the Bears combined rank would be [2+3=] 5. In 2006, the Bears would've won this particular tiebreaker against every other team. I'm guessing, but I assume when teams tie (like Colts & Bears in points scored) they both get the same rank value - in this case 2.

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