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What is A football kicked off at an angle 20 from the ground reaches a maximum height of 4.7 m What is the initial velocity of the kick?
To find the initial velocity of the kick, you can use the equation for projectile motion. The maximum height reached by the football is related to the initial vertical velocity component. By using trigonometric functions, you can determine the initial vertical velocity component and then calculate the initial velocity of the kick.
A baseball is hit straight up at an initial velocity of 100 m s how long will it take to hit the ground?
To determine how long it will take for the baseball to hit the ground after being hit straight up at an initial velocity of 100 m/s, we can use the kinematic equations of motion. The time to reach the maximum height can be calculated using the formula ( t = \frac{v}{g} ), where ( v ) is the initial velocity (100 m/s) and ( g ) is the acceleration due to gravity (approximately 9.81 m/s²). This gives us a time of about 10.2 seconds to reach the peak. Since the time to ascend and descend is equal, the total time for the baseball to hit the ground is approximately 20.4 seconds.
What is the maximum range of projectile?
The maximum range of a projectile is the distance it travels horizontally before hitting the ground. It is influenced by factors such as initial velocity, launch angle, and air resistance. In a vacuum, the maximum range is achieved at a launch angle of 45 degrees.
How does initial velocity affect the projectile in range?
The initial velocity of a projectile affects its range by determining how far the projectile will travel horizontally before hitting the ground. A higher initial velocity will result in a longer range because the projectile has more speed to overcome air resistance and travel further. Conversely, a lower initial velocity will result in a shorter range as the projectile doesn't travel as far before hitting the ground.
If a ball is thrown at an angle of 40 degrees above the horizontal at a speed of 16 meters per second from the top of a 12.4 m tall building what is the maximum height of the ball above the ground?
The maximum height of the ball above the ground can be calculated using the vertical component of the initial velocity. Assuming no air resistance, the formula to determine maximum height is h = (v^2 sin^2(theta)) / (2g), where v is the initial velocity (16 m/s), theta is the angle (40 degrees), and g is the acceleration due to gravity (9.8 m/s^2). Plugging in the values, you can find that the maximum height of the ball is approximately 14.1 meters.
Which information is needed to find the time a projectile is in motion?
The object's initial distance above the ground The object's initial velocity
Am arrow is shot straight up at an initial velocity of 250 m s how long will it take to hit the ground?
Assuming no air resistance, the arrow will take approximately 5 seconds to hit the ground because it will reach its maximum height before falling back down due to gravity. The total time for the arrow to travel up and back down is twice the time it takes to reach the maximum height.
What is the velocity of the tomato when it hits the ground?
The velocity of the tomato when it hits the ground will be determined by its initial velocity, the force of gravity acting upon it, and any air resistance. It will likely be accelerating towards the ground due to gravity until it reaches its terminal velocity upon impact.
How long does it take to hit the ground from 28000 feet high?
The answer will depend on what "it" is, and on what its initial velocity is.
How does adding initial height affect maximum range?
Adding initial height to a projectile generally increases its maximum range. This is because a higher launch point allows the projectile to have a longer flight time and greater horizontal distance before it hits the ground, assuming all other factors remain constant. The increased vertical distance also means that the projectile can take advantage of its initial velocity for a longer duration, enhancing its overall travel distance. However, the effect depends on the angle of launch and initial velocity as well.
If a cricket jumps off the ground with an initial vertical velocity of 4 ft per second afer how many seconds does the cricket land on ground?
To determine how long it takes for the cricket to land back on the ground after jumping with an initial vertical velocity of 4 ft per second, we can use the formula for the time of flight in projectile motion. The time to reach the maximum height is given by ( t = \frac{v}{g} ), where ( v ) is the initial velocity and ( g ) is the acceleration due to gravity (approximately 32 ft/s²). In this case, it takes ( t = \frac{4}{32} = 0.125 ) seconds to reach the peak. Since the time to ascend and descend is equal, the total time until the cricket lands back on the ground is ( 2 \times 0.125 = 0.25 ) seconds.
Will a ball drop rest reach the ground quicker than the one lunched from the same height but with and initial horizontal velocity?
No. What counts in this case is the vertical component of the velocity, and the initial vertical velocity is zero, one way or another.
