No.
However, the statement is true provided that the vertical component of the launch velocity for the two motions are the same.
You also require that both motions end at the same level and that the air resistance etc can be disregarded. The first of these may not always be valid in school exercises, the second is usually implicit.
To determine the vertical velocity of a projectile, you can use the formula: vertical velocity initial vertical velocity (acceleration due to gravity x time). The initial vertical velocity is the speed at which the projectile is launched upwards or downwards. Acceleration due to gravity is typically -9.8 m/s2 (negative because it acts downwards). Time is the duration for which the projectile has been in motion. By plugging in these values, you can calculate the vertical velocity of the projectile.
Velocity is the time rate of change of displacement of an object. Velocity is the distance travelled in unit time in a stated direction. It is a vector quantity since it gives us both magnitude and direction.
To draw a velocity-time graph for a body thrown vertically upwards, the initial velocity will be positive (upwards) and steadily decrease due to gravity until reaching zero at the peak. After the peak, the velocity becomes negative as the body falls back down. The graph will have a symmetrical shape with the velocity decreasing and then increasing back to the initial velocity.
In the act of "throwing", the thrower imparts an upward velocity to the object, by temporarily applying an upward force to it that's greater than the downward force of gravity. During that brief period, the sum of the forces on the object is directed upward, so it accelerates in that direction. After the throwing ends, however, the only force on the object is the force of gravity, directed downward, so its acceleration is downward. That means that the upward velocity becomes smaller and smaller, until it's zero at the peak of the arc, and the velocity then becomes downward as the object begins to fall from its peak..
Yes, it is possible for the initial velocity to be different from zero when the final velocity is zero. For example, an object could be thrown upwards and come to a stop at its highest point, where the final velocity would be zero.
45 degrees to the horizontal will give the maximum flight time for a projectile. If a projectile was fired at 90 degrees to the horizontal, (straight upwards) the projectile will go straight upwards (ignoring the shape, form and aerodynamic properties of the projectile). Likewise if you were to fire a projectile at 0 degrees to the horizontal, the projectile would follow said course, IF gravity was not in effect; a projectile needs some form of vertical velocity to overcome gravity. Hence why 45 degrees will give you the longest distance and consequently flight time.
The vertical component of a projectile's velocity is irrelevant. It can be up, down, or zero, makes no difference. As long as projectile motion lasts ... gravity is the only force on the object and you're ignoring air resistance ... its acceleration is constant, and is equal to the acceleration of gravity: 9.8 meters per second2 pointing down.
A projectile will travel on a straight line unless external forces act upon it. Gravity will pull the projectile downward, i.e. affect its vertical velocity component. This is why the projectile will decelerate upwards, reach a maximum elevation, and accelerate back down to earth. The force vector of air resistance points in the opposite direction of motion, slowing the projectile down. For example, If the projectile is going forward and up, air resistance is pushing it backwards (horizontal component) and down (vertical component). Without air resistance, there is no external force acting upon the horizontal velocity component and the projectiles ground speed will stay constant as it gains altitude and falls back down to earth.
The gravity acting on a rising object and that on a falling object are the same when these objects are at the same height. What is different is that a rising object is decelerating by the force of gravity and the falling object is accelerating.
To find the initial velocity with which the object is thrown upwards, we can use the kinematic equation for vertical motion: ( v = u + at ), where ( v ) is the final velocity (0 m/s at the highest point), ( u ) is the initial velocity, ( a ) is the acceleration due to gravity (-9.81 m/s²), and ( t ) is the time taken to reach the highest point (half the total time to reach the ground, so 2 seconds in this case). Rearranging the equation to solve for ( u ), we get ( u = v - at ). Plugging in the values, we get ( u = 0 - (-9.81 m/s² * 2 s) = 19.62 m/s ). Therefore, the object was thrown upwards with an initial velocity of 19.62 m/s.
When an object is moving upwards, its velocity is directed upwards. If the object is near the Earth or any other planet, then its acceleration is directed downwards, which also means that its upward velocity is decreasing.
Circular motion is a type of two-dimensional motion that is not always projectile motion. In circular motion, such as a car driving around a curve or a satellite orbiting a planet, the object is constantly changing its direction without necessarily being launched upwards. This motion can involve acceleration due to the changes in velocity direction.