In a Little League baseball game the 145 g ball enters the strike zone with a speed of 15.0 ms The batter hits the ball and it leaves his bat with a speed of 20.0 ms in exactly the opposite direction?

Answer 1

Im taking ms for m/s.

the magnitude of the impulse= (px)i=m(vxi)=(0.145kg)(-15.0m/s)=-2.2N

(px)f=m(vx)f=(0.145kg)(20.0m/s)=2.9N

Delta Px =(px)f-(px)i= 2.9N-(-2.2N)=5.1N or 5.1 kg m/s

If the bat is in contact with the ball for 1.5 ms the magnitude of the avg force exerted on the bat is:

Favg= J/Delta t

1.5 ms=0.0015 s

Favg= (5.1 kg m/s)/0.0015

= 3400N