The general formula for the number of combinations of r things chosen from n different things is C(n,r) = n!/ r!(n-r)! How many ways can 5 players be chosen from a team of 13?
(Where the order you choose the players does not matter).
So C(13,5) = 13!/5!(13-5)!
Or 1,287
The first position can be filled by eight, the second by seven, and so on. So the number of possibilities are: 8!/3! = 8*7*6*5*4 = 6720
1
5
200
A typical basketball team has at least 5 members because 5 people are needed to be on the court to play the 5 positions.
There are 5 different positions on a basketball team. Point Guard, Shooting Guard, Small Forward, Power Forward, and Center
Their is five starting players.
Depends on how many horses are racing. I'm no pro, but I've seen up to 14 horses racing, which would mean there can be up to 14 starting positions in a race.
There are four positions that need to be filled in the barracks.
Since there were many of them, the positions wer probably filled by "extras."
only 12 can dress in the NBA
Three positions need to be filled to get the maiden's tower operational.