They might seem like they have the same flight patterns, but they don't. A 12-6 curveball thrown by an over-hander will go from 12 to 6, but if the same is thrown by a 3/4 or side-armer, the ball will react a little more like a slider.
90
Ignoring air resistance, I get this formula:Maximum height of a vertically-launched object = 1.5 square of initial speed/GI could be wrong. In that case, the unused portion of my fee will be cheerfully refunded.
The speed decreases when an object is thrown vertically up because of the force of gravity acting against the object's upward motion. As the object goes higher, the force of gravity slows it down until the object reaches its maximum height, where its speed momentarily becomes zero before accelerating back downward.
The maximum height hmax that a ball reaches when thrown into the air is the highest point it reaches before falling back down.
A ball has the greatest potential energy at its highest point, such as when it is held at the top of a hill or at its maximum height when thrown vertically upwards. This is because the gravitational force acting on the ball is at its maximum, giving it the highest potential energy.
An object thrown vertically up wards from the ground returned back to the ground in 6s after it was thown up if it reached a height of 12m calculate?
if the bal is thrown by making 45 degree angles. with the ground..it will travel maximum distance...
apply the formula: v2 - u2 = 2as. Here v= 0; u = 19.6m/s; a = -g ,find s and that's max. heigth
The body will continue to rise until the force of gravity acting against its motion brings it to a stop before it falls back down to its starting position due to gravity pulling it back down. The total time of flight and maximum height reached depend on the initial velocity of the body and the acceleration due to gravity.
The total time of flight for a ball thrown vertically upwards and returning to its starting point is twice the time taken to reach maximum height. Therefore, the time taken to reach maximum height is 4 seconds. Given that the acceleration due to gravity is -9.8 m/s^2, using the kinematic equation v = u + at, where v is the final velocity (0 m/s at maximum height), u is the initial velocity, a is the acceleration due to gravity, and t is the time, you can solve for the initial velocity. Substituting the values, u = 9.8 * 4 = 39.2 m/s. Therefore, the initial velocity of the ball thrown vertically upward is 39.2 m/s.
If you ignore air resistance, then they will reach their maximum height at the same time. In order not to ignore air resistance, you would need to know their shapes.
The ball has maximum potential energy at its highest point, which is at a height of 15 meters when it is thrown into the air.