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Yes. Faster = farther.

Q: Does the swing velocity of a bat affect the distance the ball will travel?

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No, the length of the pendulum does not affect the speed at which it swings. The time it takes for one complete swing (period) is only influenced by the force of gravity and the starting angle of the swing.

The biggest affect with age is the flexibility of the body. As the player gets older his/her flexibility decreases and thus the width that they can swing. The result is typically lost distance and power.

The length of the string in a pendulum affects the period of its swing. A longer string will have a longer period, meaning it will take more time to complete one full swing. This is due to the increased distance the pendulum has to travel, leading to a slower back-and-forth motion.

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no the bob on the shorter one has less distance per period to travel

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Follow-through doesn't affect the force, if thats what your think. It actually increase the velocity. Follow-through means more time of collision

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Yes, the weight of a bat can affect hitting distance. Heavier bats can generate more power and distance but may sacrifice speed, while lighter bats offer more control and faster swing speed, which can impact hitting distance as well. It ultimately depends on the player's preference and abilities.

A bat hitting a baseball is an elastic collision which means there is a transfer of momentum from the bat to the ball. Since momentum is equal to mass multiplied by velocity, a higher mass means more momentum. However, you also must consider that it is harder to swing a heavier bat and therefore it will travel slower and therefore have less momentum.

The minimum angular velocity required to prevent spilling water is given by the equation ω = sqrt(g/L), where g is the acceleration due to gravity (approximately 9.81 m/s^2) and L is the length of the arms in meters (63 cm = 0.63 m). The distance from the handle to the center where the bucket is hanging does not affect this calculation. Thus, the minimum angular velocity can be calculated as ω = sqrt(9.81/0.63) ≈ 4.37 rad/s.