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90 feet

Q: Distance between first base and 2nd base?

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The distance of 90 feet (between home and first) is the distance of the middle of the plate and the middle of first base.

99 feet. You can find the distance between home and second on any baseball or softball field by using the following formula: A squared plus B squared equals C squared. A is the distance between home and first base B is the distance between first base and second base C is the distance between home and second base.

100.623 feet if playing in the baseline exactly between 2nd and 3rd

This is because the rules of baseball say the mound is a distance from homeplate that is less than halfway the distance between homeplate and 2nd base. The distance is the same between each base in order (the same from home to 1st, 1st to 2nd, 2nd to 3rd, 3rd to home.) This results in the distance between homeplate and 2nd equal to the distance between 1st and 3rd. If you draw a line between homeplate and 2nd, and a line between 1st and 3rd, the lines will intersect in the center of the baseball diamond. However, the center point will be behind the pitcher's mound. You can use the Pythagorean Theorem to prove the distance from the mound to home is less than the center point, but that is another question. (Hint: The distance squared from home to first plus the distance squared from first to second divided by 2).

the distance between all the bases in major league baseball is 90 feet. home --> first first--> second second--> third third--> home all are 90 feet apart

Pythagorean Theorem. We know its 90 feet between the bases, and we know that you're describing a right triangle, so we can figure the distance between home plate and second base as: 90^2 + 90^2 = x^2 8100 + 8100 = x^2 16200 = x^2 127.29 feet

60 ft

The distance between every single base in softball is 60 feet. The distance to the pitcher's mound from home is either 40 or 43 feet depending on what level you are playing at. The outfield depth varies from field to field.

Do the math by using pythagoream therom. make a triangle using homeplate first base and second base with the bases being 90 ft apart. the distance from home plate to 2nd base comes out to 127ft 4in.

How far is it from 2nd base to center field? The distance from home plate to 2nd base is 127.28 feet (use pythagorean theorem z^2 = x^2 + y^2 or z = sqrt(x^2 + y^2)), so the distance from 2nd base to the fence in dead center is 277.72 feet.

The distance from home plate to first base is 90 feet and the distance from first base to second base is also 90 feet making a right angle; you can calculate how far the catcher needs to throw to 2nd base from home by Pythagorean theorem. Answer is 127.3 feet

The distance is measured from the back of home plate to the back corner of 2nd base. The distance is 127 feet 3 3/8 inches.