Q: A tennis ball is dropped from 1.55 m above the ground It rebounds to a height of 0.824 mWith what velocity does it hit the ground?

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The ball dropped from 4m height has more kinetic energy just before it hits the ground because it has a higher velocity due to falling from a greater height. Kinetic energy is directly proportional to both mass and the square of velocity, so the ball dropped from 4m height will have more kinetic energy than the one dropped from 2m height.

Increasing the height from which a ball is dropped will result in a higher bounce because the ball gains more potential energy as it falls from a greater height. This increase in potential energy translates to a greater kinetic energy upon impact with the ground, leading to a higher bounce.

The height from which an object is dropped does not affect its average velocity. Average velocity depends on the overall displacement and time taken to achieve that displacement, regardless of the initial height of the object.

The velocity-time graph for a body dropped from a certain height would show an initial spike in velocity as the object accelerates due to gravity, reaching a maximum velocity when air resistance equals the force of gravity. After this, the velocity would remain constant, representing free fall with a terminal velocity. When the object hits the ground, the velocity suddenly drops to zero.

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No, both balls will hit the ground at the same time, assuming they are dropped from the same height and in a vacuum. The horizontal velocity does not affect the time it takes for an object to fall vertically due to gravity.

You can measure how high a ball bounces by dropping it from a certain height and then measuring the height it rebounds to. The ratio of the height it rebounds to the height it was dropped from gives you an idea of the ball's elasticity or bounciness.

To compare the original height of a ball to its rebound height, you can measure the height the ball was dropped from and then measure the height it rebounds to after bouncing. The rebound height will likely be lower than the original height due to energy loss during the bounce. By comparing the two heights, you can calculate the percentage of energy lost during the rebound.

The height of the ball when it rebounds is 5 meters, as given in the question.

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The velocity of the stone dropped from a height of 318 meters can be calculated using the formula v = √(2gh), where g is the acceleration due to gravity (9.81 m/s^2) and h is the height (318 m). Substituting the values, the velocity of the stone would be approximately 78.74 m/s.

When an object is dropped from a height, gravity causes it to accelerate towards the ground. This acceleration leads to a change in velocity as the object's speed increases. The change in velocity occurs because gravity exerts a force on the object, pulling it towards the Earth.