Q: What is done when a baseball is lifted 0.7 m?

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The work done is equal to the force needed to lift the mass multiplied by the vertical distance lifted. In this case, the work done is equal to the gravitational force acting on the mass (m x g) multiplied by the vertical distance lifted (1 m). So, the work done would be 1 kg * 9.8 m/s^2 * 1 m = 9.8 Joules.

100 J

The work done lifting the tomato against gravity is calculated as the product of its weight (force due to gravity) and the vertical distance it is lifted. The weight of the tomato is 195g * 9.81 m/sĀ² = 1.91 N. Therefore, the work done lifting the tomato is 1.91 N * 19.4 m = 37.03 Joules.

2,088 J

Work = force * distance Work = 23N * 2.3 meters = 53 Joules of work is done ==================

The work done is equal to the change in potential energy, which can be calculated as (mass x gravity x height). Plugging in the values: (200 kg x 9.8 m/s^2 x 5 m) = 9800 J. Therefore, 9800 joules of work are done when the box is lifted 5 meters above the floor.

The work done is 34 kJ. Work done is calculated as force x distance, which in this case is 34 N x 1000 m = 34 kJ.

The potential energy gained by the baseball can be calculated as the product of the force applied (10 N) and the distance lifted (10 m). Thus, the potential energy gained would be 100 J.

The work done when lifting the tomato is equal to the force required to lift it multiplied by the distance it is lifted. The force can be calculated using the formula F = mg, where m is the mass of the tomato and g is the acceleration due to gravity. Once the force is calculated, multiply it by the distance lifted to get the work done.

980 w=m x g x d

M. Karathu was born on 1943-07-07.

The work done can be calculated using the formula: Work = force x distance. In this case, Work = 20 N x 5 m = 100 joules. Therefore, 100 joules of work are done when a 20 newton box is lifted 5 meters off the floor.