In most sport when a coach makes up a play he uses x's and o's. But in football where the rules are different for every player he uses X's and Z's for the wide recievers.
first of all, what does ZZ stand for? Z x Z? or just Z (the integers)? I can answer better if I know the sets you are talking about.
X, Y, and Z are all variables. When writing an equation they can stand for whatever you want them to, but when solving an equation that is what you typically are trying to find out. EX: 7x-7= 14 you would add 7 to both sides giving you 7x=21 and then solve for x which would be 7x/7=21/7 or x=3
logbase5 of x =z x=5^z
If x = y and y = z then x = z
"Z" stands for zodiac
The Z in Jay-Z doesn't stand for anything. The name Jay-Z is just a spinnoff of his mentor's name "Jazz".
There are 8 different subsets. The null set. {x} {y} {z} {x y} {x z} {y z} {x y z}
To determine the value of the expression x-a x-b x-c x-z, we need to consider the factors of the expression. Since each letter of the alphabet (excluding x) is subtracted from x in one of the factors, there are a total of 26 factors. This means that the expression must be expanded to include all 26 letters of the alphabet as factors, resulting in x-a x-b x-c ... x-z. Therefore, the value of the expression is x-a x-b x-c ... x-z.
Commutative x + y = y + x x . y = y . x Associative x+(y+z) = (x+y)+z = x+y+z x.(y.z) = (x.y).z = x.y.z Distributive x.(y+z) = x.y + x.z (w+x)(y+z) = wy + xy + wz + xz x + xy = x x + x'y = x + y where, x & y & z are inputs.
if X(Z) is a Z-transform of x[n] and X(Z) is causal then the initial value theorem states that the lim as z tends to infinity for X(Z) must eqaul x(0).
If z = 3, what is 5 x (6 – z)?
x + 1 = y y + 3 = z z = y + 3 = (x + 1) + 3 = x + 4 Or: x = y - 1 = (z - 3) - 1 = z - 4 Which results in the same: x exceeds z by 4.