"O-G-G" in text talk could mean "Oh God, Girl." It is often used to express surprise, shock, or disbelief in a dramatic or humorous way.
oh goodness gracious
lawllz in text talk is another way to lol. it's just extended. when you say l-o-ls it sounds like lawllz.
To find the number of moles of nitrogen in 89.0 g of N₂O, first determine the molar mass of N₂O, which is approximately 44.01 g/mol (with nitrogen contributing about 28.02 g and oxygen about 16.00 g). Using the formula ( \text{moles} = \frac{\text{mass}}{\text{molar mass}} ), we calculate the moles of N₂O: ( \frac{89.0 , \text{g}}{44.01 , \text{g/mol}} \approx 2.02 , \text{moles of N₂O} ). Since each molecule of N₂O contains two nitrogen atoms, the total moles of nitrogen is ( 2.02 \times 2 \approx 4.04 ) moles of nitrogen (N).
According to the balanced equation (2 \text{H}_2(g) + \text{O}_2(g) \rightarrow 2 \text{H}_2\text{O}(g)), 2 moles of hydrogen react with 1 mole of oxygen. Therefore, to find the number of moles of hydrogen needed for 0.234 moles of oxygen, you can use the ratio: (0.234 , \text{mol O}_2 \times \frac{2 , \text{mol H}_2}{1 , \text{mol O}_2} = 0.468 , \text{mol H}_2). Thus, 0.468 moles of hydrogen are required.
To determine the mass of nitrous oxide (N₂O) that can be formed from 54.7 g of nitrogen (N₂), we first need to understand the balanced chemical reaction for the synthesis of nitrous oxide, which is: [ N_2 + O_2 \rightarrow 2N_2O ] From the molar mass of nitrogen (28.02 g/mol), we can find the number of moles in 54.7 g of nitrogen: [ \text{Moles of } N_2 = \frac{54.7 \text{ g}}{28.02 \text{ g/mol}} \approx 1.95 \text{ moles} ] According to the reaction, 1 mole of N₂ produces 2 moles of N₂O, so 1.95 moles of N₂ would produce 3.9 moles of N₂O. The molar mass of N₂O is approximately 44.01 g/mol, thus: [ \text{Mass of } N_2O = 3.9 \text{ moles} \times 44.01 \text{ g/mol} \approx 171.63 \text{ g} ] Therefore, about 171.63 g of nitrous oxide can be formed from 54.7 g of nitrogen.
To determine which reaction has a decrease in entropy, we look at the change in the number of gas molecules. A decrease in entropy typically occurs when the number of gas molecules decreases from reactants to products. Among the reactions provided, the formation of ( \text{N}_2\text{O}_4(g) ) from ( 2\text{NO}_2(g) ) results in a decrease in the total number of gas molecules (from 2 moles of ( \text{NO}_2 ) to 1 mole of ( \text{N}_2\text{O}_4 )), indicating a decrease in entropy.
n n n n n n n n n n n n n n n o o o o o o o o o o o o o t t t t t t t t t t t h h h h h h h h h h h h h h i i i i i i i i i i n n n n n n n n n n g g g g g g gg g g g g g g g gg gg g
NO!
2 O's in Google and Yahoo!
Density is calculated using the formula ( \text{Density} = \frac{\text{Mass}}{\text{Volume}} ). For an object with a mass of 60 grams and a volume of 8 cm³, the density would be ( \frac{60 , \text{g}}{8 , \text{cm}^3} = 7.5 , \text{g/cm}^3 ). Therefore, the density of the object is 7.5 g/cm³.
it means he wants space give him time to think and recover and next thing you know you will be :-