you are not born with the talent of throwing a Baseball hard. all you have to do is work out a little bit.after that u practce throwing a baseball.try different ways of throwing it see wat fits u. watch baseball games and see how they throw after seeing them you might wanna try doing wat the do
There is a new baselayer out which increase velocity for pitching, batting and running Its by a company called asus you can find them at www.asus.uk.com I bought one and it works for me . good luck
This is how you throw a baseball really hard. You take the ball and put your two fingers, the middle and the pointer you take those fingers put it on the top of the ball. The other fingers at the bottom of the ball. Then you raise your arm above your head and throw it as hard as you can. Make sure that you throw it when somebody is looking but make sure to throw it strait.
First you eye ball the tether ball lift it up twice and then hit it not to hard or you will mess up only hit with your wrist when serving then you will win and hit it hard.
Also don't hit hard hit soft.
Sincerely Tether Master 101
Try using your legs, When you push off with your legs you put less strain on your throwing arm. If you watch MLB pitchers, pay close attention to the way they push off the mound when they pitch. When you learn to coordinate your push off with your throwing motion, it will help you throw a lot harder
place your two fingers (index+middle) on the seams of the baseball and then throw it
Practice, and practice. Theres no secret.
work at it
If the ball is inflated (like a basketball or soccer ball) it will become harder as external air pressure is reduced. This will make it bounce higher. It will become softer as external air pressure is increased. It won't bounce as high then and eventually, as it becomes soft enough, it won't bounce at all. These statements assume that no air is added to or removed from the interior of the ball. I'm not sure what the effect would be on a solid rubber ball.
Yes. According to Newton's third law of physics, a force exerted by one body (you) onto another body (the ball), will always have a returning force equal in magnitude and opposite in direction. In simpler terms, the force that you apply to the ball by pushing it will also be applied to you by the ball. However, because the ball has less mass, the ball will gain significantly more speed than you will.
That will depend not only on the escape velocity, but also - very importantly - on the object's speed.
Yes The equation for momentum is mass x velocity So if you increase velocity the momentum increases
A gain of 9 yards is when the offense moves the ball forward 9 yards from the line of scrimmage by either running the ball or passing the ball to a receiver/pass catcher.
The change in velocity, in this case, is equal to acceleration x time.
The way I do it is that I hold in between the two seems with closed fingers and crack your arm forward like make an L with your arm sticking up, raise your arm and crack forward. Also when you are doing it you flex your muscle and stop flexing it when you release the ball you stop flexing and you throw as hard as you possibly could. im 11 and with this technique i reach up to 60mph (96kph).
When the ball leave your hand it goes up with an initial velocity v0 so that the action of your hand gives the ball the kinetic energy K=0.5 M v02 where M is the ball mass. When the ball goes up the kinetic energy decreases: a part is converted in potential energy while the balls is higher and higher and part is dissipates due to the attrition with air (that more precisely is due to air viscosity) and to the fact that air particles are put in motion by the arrival of the ball so that they gain kinetic energy at the expenses of the kinetic energy of the ball due to collision. Neglecting the last term that, due to the small density of air with respect to the ball is generally quite small, the viscosity dissipate energy mainly by generating heat. When the ball stops at maximum height the kinetic energy is reduced to zero (the velocity is zero) and all the energy is potential, while a certain amount of heat has been dissipated during the motion. If we call Q the quantity of generated heat and h the maximum height reached by the ball, for the energy conservation rule we have 0.5 M v02=Q+M g h If the air viscosity is negligible, or if the ball goes up in vacuum, Q is zero and we can deduce the maximum height the ball reaches h=(M v02)/( 2 M g)
No it can't. But it makes you throw up and have diarrhea.
At the radius of the earths surface, a body will gain roughly 10 metres per second velocity every second. (air resistance ignored) See google / acceleration due to gravity.