Friction is the force that keeps you from sliding off a sled when it starts moving. When you sit on a sled, the friction between the sled and your clothing provides the necessary grip to keep you in place as the sled accelerates.
Air resistance is a force that opposes the motion of an object moving through the air. When a sled is moving through the air, the air molecules collide with the sled, creating friction and slowing it down. This force becomes more prominent as the speed of the sled increases.
To keep a sled accelerating downhill, the force of gravity must be greater than the force of friction acting against the sled. This allows gravity to overcome the frictional force and propel the sled forward.
Yes, when a sled is accelerating downhill, the force of gravity pulling the sled downhill must be greater than the normal force acting in the opposite direction to overcome friction and any other resistive forces. This difference in force is what allows the sled to accelerate downhill.
A sled accelerates downhill when the force of gravity pulling it downhill is greater than the force of friction and air resistance acting against it. This difference creates a net force that causes the sled to accelerate. The normal force from the surface helps support the sled against gravity but does not impact its acceleration directly.
Friction is the force that keeps you from sliding off a sled when it starts moving. When you sit on a sled, the friction between the sled and your clothing provides the necessary grip to keep you in place as the sled accelerates.
Air resistance is a force that opposes the motion of an object moving through the air. When a sled is moving through the air, the air molecules collide with the sled, creating friction and slowing it down. This force becomes more prominent as the speed of the sled increases.
The acceleration is caused by the force of gravity on the sled combined with the force you exert on the sled by pushing it.
To keep a sled accelerating downhill, the force of gravity must be greater than the force of friction acting against the sled. This allows gravity to overcome the frictional force and propel the sled forward.
The force exerted on the sled can be calculated using Newton's second law: force = mass x acceleration. Plugging in the values, the force exerted on the sled would be 260 Newtons (N).
Yes, when a sled is accelerating downhill, the force of gravity pulling the sled downhill must be greater than the normal force acting in the opposite direction to overcome friction and any other resistive forces. This difference in force is what allows the sled to accelerate downhill.
A sled accelerates downhill when the force of gravity pulling it downhill is greater than the force of friction and air resistance acting against it. This difference creates a net force that causes the sled to accelerate. The normal force from the surface helps support the sled against gravity but does not impact its acceleration directly.
If the force on the right sled were larger, its acceleration would increase. This is because acceleration is directly proportional to force according to Newton's second law of motion. The larger force would result in a greater acceleration of the sled.
When you pull a sled through the snow, the force applied to overcome friction between the sled and the snow does work. The force that is perpendicular to the direction of motion (such as lifting the sled slightly off the ground) doesn't do work, as it doesn't contribute to the displacement of the sled. Work is only done by a force component in the direction of the displacement.
friction
The force of friction is proportional to the force which surfaces press against each other. Since two people will cause the sled to push harder on the snow then one person, the friction will be greater for two people on the sled.
To find the force of friction between the sled and the snow, we need to resolve the applied force into its components. The force acting parallel to the ground (F_parallel) will balance the force of friction, so F_friction = F_parallel. Using trigonometry, F_parallel = 80 * cos(53). Thus, the force of friction between the sled and the snow is 50.63 N.