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The force that holds you to a sled when it starts moving is friction between your body and the sled, as well as the force of gravity acting on you downwards. As the sled accelerates, friction between your body and the sled helps keep you in place and in motion together.

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friction

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Q: What force holds you to a sled when it starts moving?
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What is the force that keeps you from sliding off a sled when it starts moving?

Friction is the force that keeps you from sliding off a sled when it starts moving. When you sit on a sled, the friction between the sled and your clothing provides the necessary grip to keep you in place as the sled accelerates.


What is air resistance that slows down a sled?

Air resistance is a force that opposes the motion of an object moving through the air. When a sled is moving through the air, the air molecules collide with the sled, creating friction and slowing it down. This force becomes more prominent as the speed of the sled increases.


To keep a sled accelerating downhill what must the force of gravity be greater than?

To keep a sled accelerating downhill, the force of gravity must be greater than the force of friction acting against the sled. This allows gravity to overcome the frictional force and propel the sled forward.


Is it true that a sled accelerating downhill the force of gravity must be greater than the normal force?

Yes, when a sled is accelerating downhill, the force of gravity pulling the sled downhill must be greater than the normal force acting in the opposite direction to overcome friction and any other resistive forces. This difference in force is what allows the sled to accelerate downhill.


To keep a sled accelerating downhill the force of gravity must be greater than the normal force?

A sled accelerates downhill when the force of gravity pulling it downhill is greater than the force of friction and air resistance acting against it. This difference creates a net force that causes the sled to accelerate. The normal force from the surface helps support the sled against gravity but does not impact its acceleration directly.

Related questions

What is the force that keeps you from sliding off a sled when it starts moving?

Friction is the force that keeps you from sliding off a sled when it starts moving. When you sit on a sled, the friction between the sled and your clothing provides the necessary grip to keep you in place as the sled accelerates.


What is air resistance that slows down a sled?

Air resistance is a force that opposes the motion of an object moving through the air. When a sled is moving through the air, the air molecules collide with the sled, creating friction and slowing it down. This force becomes more prominent as the speed of the sled increases.


When you push on a sled and it begins to go downhill you cause what accelartion?

The acceleration is caused by the force of gravity on the sled combined with the force you exert on the sled by pushing it.


To keep a sled accelerating downhill what must the force of gravity be greater than?

To keep a sled accelerating downhill, the force of gravity must be greater than the force of friction acting against the sled. This allows gravity to overcome the frictional force and propel the sled forward.


How much force is excerted on a sled if the mass of the sled is 65kg and the acceleration is 4 ms2?

The force exerted on the sled can be calculated using Newton's second law: force = mass x acceleration. Plugging in the values, the force exerted on the sled would be 260 Newtons (N).


Is it true that a sled accelerating downhill the force of gravity must be greater than the normal force?

Yes, when a sled is accelerating downhill, the force of gravity pulling the sled downhill must be greater than the normal force acting in the opposite direction to overcome friction and any other resistive forces. This difference in force is what allows the sled to accelerate downhill.


To keep a sled accelerating downhill the force of gravity must be greater than the normal force?

A sled accelerates downhill when the force of gravity pulling it downhill is greater than the force of friction and air resistance acting against it. This difference creates a net force that causes the sled to accelerate. The normal force from the surface helps support the sled against gravity but does not impact its acceleration directly.


How would the acceleration of the right sled change up if the force were larger?

If the force on the right sled were larger, its acceleration would increase. This is because acceleration is directly proportional to force according to Newton's second law of motion. The larger force would result in a greater acceleration of the sled.


When you pull a sled through the snow why does only part of your force do work?

When you pull a sled through the snow, the force applied to overcome friction between the sled and the snow does work. The force that is perpendicular to the direction of motion (such as lifting the sled slightly off the ground) doesn't do work, as it doesn't contribute to the displacement of the sled. Work is only done by a force component in the direction of the displacement.


What stops a motion of a sled moving down a snowy hill?

friction


Is the force of friction greater between two children on a sled and the snow or between only one of the children on the same sled and the snow?

The force of friction is proportional to the force which surfaces press against each other. Since two people will cause the sled to push harder on the snow then one person, the friction will be greater for two people on the sled.


If a force of 80 newtons is being applied to the sled rope at an angle of 53 degrees to the ground what is the force of friction between the sled and the snow?

To find the force of friction between the sled and the snow, we need to resolve the applied force into its components. The force acting parallel to the ground (F_parallel) will balance the force of friction, so F_friction = F_parallel. Using trigonometry, F_parallel = 80 * cos(53). Thus, the force of friction between the sled and the snow is 50.63 N.