H&B Craker Jack Baseball BatI'm not familiar with this particular variation of the Cracker Jack Bat. The Craker Jack baseball bats are commonly found on eBay selling for about $40.00 in excellent condition. Size and condition are important on putting a value on the bat. The Craker Jack was an inexpensive kids baseball bat carried for years in the Hillerich & Bradsy line of store model retail bats. The Cracker Jack model has nothing to do with the caramel coated popcorn snack as some people believe. If anything the naming of the bat was a marketing ploy to sell bats off of the popularity of the snack.The bats were being sold by H&B from about the 1920's through the 1950's, and maybe into the 1960's. More information would be needed on the markings on the bat to date your particular bat. I will leave a link below (Related Links) to help you date your baseball bat. It might be difficult to date the bat. If it has the H&B label. The earlier H&B labels have a "question mark like" engraving on each side of the H&B logo.Some Cracker Jack bats read Hillerich & Bradsby Co. above the "Cracker Jack" center oval, and Louisville, KY below. This might be difficult to date as well but if it has the question mark like" engraving on each side it should date to the 1920's -1930's
(b+h)(b+h)= b2+2hb+h2.
b/h
There is no figure given!!!! However, In a triangle the three angles are A B & 90 degrees. The sides opposite to A,B, & 90 are 'a' , 'b' & 'h' respectively. Hence Sin A = a/h SinB = b/h CosA = a/h ( Check ; 'a/h') Csc B ( CosecantB) = 1/ (a/h) = h/a CotB = CosB / SinB = (a/h) / (b/h) = a/b
If an additional B is added to the reaction, the reaction will be more likely to proceed towards completion, as there will be more B molecules available to react with KL and H. This may lead to an increase in the amount of product formed, depending on the stoichiometry and conditions of the reaction.
You cannot. If the base is B and the height is H any of the following will give an area of 13: B = 13, H = 1 B = 130, H = 0.1 B = 1300, H = 0.01 etc. Or, B = 6.5, H = 2 B = 65, H = 0.2 etc Or B = 2.6, H = 5 B = 26, H = 0.5 etc I hope you get the idea.
H&B Craker Jack Baseball BatThe Craker Jack baseball bats are commonly found on eBay selling for about $40.00 in excellent condition. Size and condition are important on putting a value on the bat. The Craker Jack was an inexpensive kids baseball bat carried for years in the Hillerich & Bradsy line of store model retail bats. The Cracker Jack model has nothing to do with the caramel coated popcorn snack as some people believe. If anything the naming of the bat was a marketing ploy to sell bats off of the popularity of the snack.The bats were being sold by H&B from about the 1920's through the 1950's, and maybe into the 1960's. More information would be needed on the markings on the bat to date your particular bat. I will leave a link below (Related Links) to help you date your baseball bat. It might be difficult to date the bat with the H&B label. The earlier H&B labels have a "question mark like" engraving on each side of the H&B logo.More informationThe Bat you have was probobly made during the 1920-1930's ers. There is not much more I can tell you. Visit the link the below (Related Links) to a no. 02 Cracker Jack special like the bat you have. Pictures are posted and if you need more help add it to that post.
A = h/2*(a + b) So 2A/h = a + b and therefore, a = 2A/h - b
v=B*H B= area of the Base so... v= (b*h)*h
naa aay to acha h
The bats that have the H&B brand in the oval trademark, rather than Louisville Slugger are harder to date. The H&B brand denotes a lower grade and lower priced retail bat. These bats were produced from the 1020's through the 1970's. The year the bat was made could effect the value.The number 50 cannot be used to date the bat. Hillerich & Bradsby Co. Louisville Slugger has used different oval center brands in their history. By identifying the center label, trade marks, and patens you can narrow down the year to what era the bat was made.
Area of a parallelogram = b*h. Call the area of parallelogram one x and two y. We now know that x = y = b(x)h(X) = b(x)h(y). Now b(x)h(x) = b(x)h(y) b(x)h(x)/b(x) = b(x)h(y)/b(x) h(x) = h(y), so the height of the second parallelogram must equal the height of the first.