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∙ 10y agoYes, though it's rare. For each child the odds of that happening genetically is 25%) so to calculate the odds of n children of heterozygotic parents having that condition would be (1/4)n
Wiki User
∙ 10y agoThere is a 25% chance that the offspring will exhibit polydactyly if both parents are heterozygous for the trait.
If both parents are heterozygous for seed shape (Rr), their offspring would have a 75% chance of producing round seeds (3 out of 4 possible combinations), assuming round seeds (R) are dominant over wrinkled seeds (r).
There are two forms of Homozygous inheritance: Homozygous Dominant, and Homozygous Recessive. In order for two parents that are Homozygous to produce a Heterozygous offspring, one of them MUST be Homozygous Dominant, and the other MUST be Homozygous Recessive.
There is a 25% chance (1 in 4) that the offspring will be homozygous for the trait. This is because when both parents are heterozygous (Aa), they can pass on either the dominant allele (A) or the recessive allele (a) to their offspring, resulting in a 1 in 4 chance of the offspring receiving the recessive allele from both parents and becoming homozygous (aa) for that trait.
Generally, if the parents are heterozygous and one allele is dominant over the other there are only 2 phenotypes and 3 genotypes. Parents Aa can produce AA, Aa and aa offspring. If the heterozygous individuals have an intermediate phenotype, then three genotypes and 3 phenotypes are possible. If 2 traits are being studied using heterozygous parents AaBb then the possible Genotypes are AABB, AABb, AAbb, AaBB, AaBb, Aabb, aaBb, aaBB, aabb which is nine genotypes. But there are 4 phenotypes. AABB AABb AaBB AaBb are phenotypically the same. aaBb, aaBB are phenotypically the same. Aabb, AAbb are phenotypically the same. aabb
The offspring of the parents are affected
There is a 25% chance that the offspring will exhibit polydactyly if both parents are heterozygous for the trait.
If they both are heterozygous and the recessive gene is blue it can happen
Both of the parents were heterozygous with the blonde hair allele, which is recessive. When there are two parents that are heterozygous, there is a 25% chance their offspring will get two of the recessive alleles. A punnett square can be useful when determining the different phenotypes and genotypes possible in offspring
It can happen when both parents are a heterozygous
If both parents are heterozygous for seed shape (Rr), their offspring would have a 75% chance of producing round seeds (3 out of 4 possible combinations), assuming round seeds (R) are dominant over wrinkled seeds (r).
A monohybrid cross between two heterozygous parents (Aa x Aa) would produce 100% heterozygous offspring. Each parent contributes one allele for the trait, resulting in all offspring being heterozygous.
no Ellie Simmonds parents has not got achondroplasia
To create a punnett square showing offspring that are heterozygous, you can cross a heterozygous parent (e.g., Aa) with a homozygous recessive parent (e.g., aa). This will result in half of the offspring being heterozygous (Aa) in the punnett square.
3:4 or 75%
A purebred organism is the offspring of two homozygous parents, having either two dominant alleles, AA or two recessive alleles, aa. A hybrid is the offspring of two heterozygous parents, Aa.
There are two forms of Homozygous inheritance: Homozygous Dominant, and Homozygous Recessive. In order for two parents that are Homozygous to produce a Heterozygous offspring, one of them MUST be Homozygous Dominant, and the other MUST be Homozygous Recessive.