It weights the same as one times the molar mass in g/mol. It is NOT important to be ideal, it even needn't to be necessarily a gas, only the kind of compound is important.
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The weight of a mole of an ideal gas depends on the specific gas being considered. The weight is given by the molar mass of the gas, which is typically expressed in grams per mole.
One mole of any atom has a mass equal to its Atomic Mass in grams therefore one mole of He has a mass of 4.003 g/mol.
The volume is 22,710 980(38) litres for the ideal gas.
The weight of the helium gas inside the balloon can be calculated using its molar mass, the Ideal Gas Law, and the given volume. Assuming standard conditions, helium gas has a molar mass of 4 grams per mole. Thus, a 22.4 liter balloon filled with helium gas would weigh approximately 32 grams.
The ideal gas constant has different values depending on the units one uses for pressure. Thus, if using atmospheres, R = 0.0821 L-atm/K-mole. If using kPa, R = 8.314 L-kPa/K-mole, and if using mm Hg, R = 62.36 L-mm Hg/K-mole.
At NTP (standard temperature and pressure), 1 mole of any ideal gas occupies approximately 22.4 liters of volume.
I will assume the ether behaves as an ideal gas. In that case, a mole (gram molecular weight) of the gas occupies 22.4 liters at STP. If 3.96 liters weigh 8.12 grams, then 22.4 liters weighs x where: 8.12/3.96 = x/22.4 Turn the crank, and 22.4 liters of ether weigh 45.9 grams, the gram molecular weight of ether.