a catapult drags you across the track
There are accelerating G's, Braking G's and cornering G's. It is the force in that direction the car and occupants are exposed to. 1 G is the for of gravity.
Yes, 4.5 G-force is considered fast and can put a significant amount of acceleration force on the body. It would typically be experienced during activities like high-speed car racing or certain roller coasters.
G force
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It depends on how you push it down. Terminal velocity (top speed) is when the driving force is matched by the two opposing drag forces, air drag force and rolling resistance force. The (constant) driving force (due to gravity) you get from : force (N) = mass (m) of bike and rider in kg * g * sine ( incline angle in degrees) ) ( g = local gravity rate (use 9.8 (m/s)/s ) ) The air drag force in newtons = drag coefficient (use 0.24) * velocity ^2 (velocity is in m/s) The (constant) rolling resistance force in newtons = m * g * cosine (incline angle ) * rolling resistance coefficient (use 0.03). Sequence : guess at top speed (in m/s), calculate the for and against forces for that speed, and adjust this guess until its zero.
Because of g force and gravity
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G force
= the (square of the velocity (m/s) * drag coefficient ) newtons if terminal velocity is known (forces balanced , no further acceleration), drag coefficient can be found. say terminal velocity(tv) = 70 m/s, acceleration due to gravity(g) = 9.8 m/s^2, mass(m) = 80kg m * g (force down) = tv^2 * drag coefficient (force up) at terminal velocity then m * g / tv^2 = drag coefficient 80 * 9.8/4 900 = 0.16
The 2013 Infiniti G-Coupe has a drag coefficient of 0.31 Cd.
The 2013 Infiniti G-Sedan has a drag coefficient of 0.29 Cd.
The 2011 Infiniti G-Convertible has a drag coefficient of 0.30 Cd.