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Answer for Total Stopping Distance If you look at total stopping distance then it will depend on the speed, reaction time, condition of stopping equipment and tire coefficient to surface being traveled on. This formula will get you close but there are variables that will effect the out come in real time. X= speed x(squared) /20 + x = total stopping distance.
Alternate Answer: Published data is 190 mph to 0 in 442 feet, so using Bringingthewood's formula for 60 mph, 60-0 is: 44 feet.
What else can I help you with?
What happen to the braking distance if the speed is doubled and why?
Hi there! Assuming that the deceleration (or negative acceleration, if you will) is constant and the same in both cases, you can use a special kinematic formula to solve the problem. The formula follows: (final velocity)^2 = (initial velocity)^2 + [ 2 * (deceleration) * (braking distance) ] Rearranged to our needs the formula reads: braking distance = [1/2] * -(initial velocity)^2 / (deceleration) * this equation assumes that the final velocity is zero If the initial speed were doubled then the general formula would read: braking distance = 2 * -(initial velocity)^2 / (deceleration) NOTICE that the two equations are the exact same except for the leading coefficients. 1/2 is assocaited with the braking distance of the normal velocity while 2 is assocated with the breaking distance of the doubled velocity. Since 2 is four times larger than 1/2, this leads us to the conclusion that the breaking distance for an object traveling at double a certain velocity would be 4x greater than the breaking distance of the object moving at the "regular" velocity.
If traveling 60 mph how many feet would it take you to stop?
On dry pavement in the average car it will take 60 ft of thinking about it, & 180 ft of braking for a total of 240 ft. Double the braking distance on wet pavement for a total of 420 ft. On snow it is anyone's guess.
What is the formula for distance as a function of acceleration and time?
Distance d=1/2 at2 is the formula.
What is the relationship between skid length and the initial velocity of a car help answer this theorotically not in formula thnkx?
In a car the maximum acceleration (deceleration) caused by breaks is about 1 g. Thus the faster the initial speed, then the greater the time AND distance needed to come to a stop will be required.
How to drive a Formula 1 car like a professional?
To drive a Formula 1 car like a professional, you need to have exceptional skills in handling high speeds, braking, and cornering. It requires intense focus, physical fitness, and understanding of aerodynamics. Professional drivers also rely on data analysis and feedback from their team to make adjustments during races. Practice, experience, and continuous learning are key to mastering the art of driving a Formula 1 car at the highest level.
What is the formula for distance traveled with constant acceleration?
If the car begins with zero speed, thenDistance = 1/2 (acceleration) x (time)2
Is computer programming useful in learning the distance formula in Algebra 1?
Computer programming is somewhat useful in learning the distance formula in Algebra 1. Learning the distance formula has more to do with your ability at mathmetics and you want to learn.
Where are the aerials on a formula 1 car?
On the nose of the car.
What is the focal distance formula used in optics to calculate the distance between the focal point and the lens or mirror?
The focal distance formula in optics is 1/f 1/do 1/di, where f is the focal length, do is the object distance, and di is the image distance. This formula is used to calculate the distance between the focal point and the lens or mirror.
What is the first formula 1 car suppiled by Honda?
The formula 1 car to be supplied by Honda was at the 1964 German GP.
What is the first Formula 1 car suppiled by Ford?
The formula 1 car to be supplied by Renault was at the 1977 British GP
What is the formula for calculating distance when an object is accelerating at a constant rate, given by the equation distance 1/2at2?
The formula for calculating distance when an object is accelerating at a constant rate is distance 1/2 acceleration time squared.
