In the game of Nim, a winning strategy involves calculating the "Nim-sum," which is the bitwise XOR of the sizes of all piles. To ensure a win, a player should aim to leave their opponent in a position where the Nim-sum equals zero after their turn. Specifically, if the Nim-sum is not zero at the start of a player's turn, they can make a move that forces it to zero, thereby maximizing their chances of winning.
Nim is a mathematical game where players take turns removing objects from piles. The outcome of the game (winning or losing) depends on the initial configuration of the piles. For Nim with piles of sizes 1 to 200, the winning strategy involves calculating the Nim-sum (the XOR of the pile sizes). If the Nim-sum is zero, the player to move is in a losing position; if it is non-zero, they can force a win with optimal play.
person always wants to win
Always. It always wins.
25
IT used to seem that way. But he hasn't won a tournament in 16 months, his longest ever period witout a win.
He doesn't always win, he has lost several times.
No!
1970
Because winners are always jerks
#include#include#include#include#includebool ask_yn (const std::string& prompt){while (true){std::cout > reply;switch (reply){case 'Y': case 'y': return true;case 'N': case 'n': return false;}std::cerr num && num)return num;std::cerr
Cheat.
beats me