Based on local pro-shops at the Golf course all over Florida
The Averages golfer in the USA Only 25- 30% can Honestly hit under 100 with no Mulligan's of any kind.
Using strict PGA tour rules 25-30% can be under 100 on average. This is what I was told I . Just think how many times you technically touch the ball or take mulligans it adds up. Thanks Quimby
80% 40% 20% 10% %5
100%
Many golfers enter in tournaments. It can be anywhere from 40-100
I'm afraid that is way off, I would say 1% of golfers fail to break 100 at one point in their life would be more accurate than the above stat. Par is set at 72 for most courses because there is 18 holes, either par 3, mostly par 4's and some par 5's, the total they add up to is 72 (some courses vary from 69-73). If par was 100 top pros would be maybe 125 under for a tournament which is just silly. The problem you have pointed out is solved by the handicap system, which allows golfers to shoot net under par.
whole under part equals 100 out of the percentage
use format, under numbers select percentage
To break 100 means it took you less than 100 strokes to finish a round (18 holes). The average golfer who only plays a couple times a year will usually consider it a good day to break 100. Say you played a course with a par of 72 that is the "standard" number of strokes to finish the round. So if you shoot a 70 then you shot 2 under par, if you shot a 75 you are 3 over par. This means to shoot 100 on a par 72 course would be 28 over par, which doesn't sound good but if you never play you'll take it.
The peak's area under the curve represents the percentage of light energy absorbed. To calculate the percentage, divide the peak's area by the total area under the curve and multiply by 100.
percentage of 1 = 100% 1 * 100% = 100%
percentage of 1 = 100%1.00 * 100% = 100%
Did you mean 41/100 as a percentage? If so it is 41%, because a percentage is a number out of 100!I would like of how I got the 41/ 100 percentage
1.00 as percentage = 100% 1.00 * 100% = 100%