0
Add your answer:
Earn +20 pts
Select which does not belong B M S K V S P M G S M P K P M S?
B
What is the geometrical proof of a-b whole square?
Given the graphic capability of this site, you are going to have to use some imagination! <---------a---------> <---a-b---><--b--> +-----------+-------+ |...............|..........| |.......P......|....Q...| |...............|..........| +-----------+-------+ |.......R......|....S....| |...............|..........| +-----------+-------+ In the above graphic, P, S and the whole figure are meant to be squares. The total area is P+Q+R+S = a2 P = (a-b)2 Q = b*(a-b) = (a-b)*b = a*b - b2 R = (a-b)*b = a*b = a*b - b2 and S = b2 Now, P = {P+Q+R+S} - Q - R - S = a2 - ab + b2 - ab + b2 - b2 = a2 - 2ab + b2
When was S. P. B. Charan born?
S. P. B. Charan was born on 1974-01-07.
When did P. B. S. Pinchback die?
P. B. S. Pinchback died on 1921-12-21.
When was P. B. S. Pinchback born?
P. B. S. Pinchback was born on 1837-05-10.
What are the two main types of rockets used?
Solid and liquid.
Prove that if a and b are rational numbers then a multiplied by b is a rational number?
If a is rational then there exist integers p and q such that a = p/q where q>0. Similarly, b = r/s for some integers r and s (s>0) Then a*b = p/q * r/s = (p*r)/(q*s) Now, since p, q r and s are integers, p*r and q*s are integers. Also, q and s > 0 means that q*s > 0 Thus a*b can be expressed as x/y where p and r are integers implies that x = p*r is an integer q and s are positive integers implies that y = q*s is a positive integer. That is, a*b is rational.
Unscramble b o q n s p e?
how to un b o q n s p e
Definition of additive law in probability?
This has to do with the union of events. If events A and B are in the set S, then the union of A and B is the set of outcomes in A or B. This means that either event A or event B, or both, can occur. P(A or B) = P(A) + P(B) - P(A and B) **P(A and B) is subtracted, since by taking P(A) + P(B), their intersection, P(A and B), has already been included. In other words, if you did not subtract it, you would be including their intersection twice. Draw a Venn Diagram to visualize. If A and B can only happen separately, i.e., they are independent events and thus P(A and B) = 0, then, P(A or B) = P(A) + P(B) - P(A and B) = P(A) + P(B) - 0 = P(A) + P(B)
What is the geometrical proof of a plus b whole square?
In view of the graphic capabilities of this site, you will need to use a fair amount of imagination! Here goes: <------a+b------> <----a----><-b-> +-----------+-----+ |. . . . . . . .|. . . .| |. . . P. . . .|. .Q. | |. . . . . . . .|. . . .| +-----------+-----+ |. . . R. . . .|. .S. | |. . . . . . . .|. . . .| +----------+-----+ Where P = a*a = a2 Q = a*b R = b*a = a*b S = b*b = b2 (a + b)2 = P + Q + R + S = a2 + ab + ab + b2 = a2 + 2ab + b2
What series of letters does not belong b m s k or v s p m or g s m p or k p m s?
bmsk
Can the product of two rational numbers be irrational?
No.Suppose a and b are two rational numbers.Then they can be written as follows: a = p/q, b = r/s where p, q, r and s are integers and q, s >0.Then a*b = (p*r)/(q*s).Using the properties of integers, p*r and q*s are integers and q*s is non-zero. So a*b can be expressed as a ratio of two integers and so the product is rational.
