0
its either (z2+ 9)(z - 2) , (z2+ 2)(z - 9) , or (z2- 9)(z - 2)
After all forces are summed with vector addition, the result is usually known as the net force (Fn) and can be used in the formula (Fn = ma).
z2 + 9z + 18 = z2 + 6z + 3z + 18 = z(z+6) + 3(z+6) = (z+6)*(z+3)
x= z2 - 3
Any pi network can be transformed to an equivalent T network. This is also known as the Wye-Delta transformation, which is the terminology used in power distribution and electrical engineering. The pi is equivalent to the Delta and the T is equivalent to the Wye (or Star) form. Pi NetworkT Network The impedances of the pi network (Za, Zb, and Zc) can be found from the impedances of the T network with the following equations: Za = ( (Z1*Z2)+(Z1*Z3)+(Z2*Z3) ) / Z2 Zb = ( (Z1*Z2)+(Z1*Z3)+(Z2*Z3) ) / Z1 Zc = ( (Z1*Z2)+(Z1*Z3)+(Z2*Z3) ) / Z3
z1,z2,
If z1=a+ib and z2=c+id then the product z1*z2=(ac-bd)+i(ad+bc)
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ax * ay = a(x+y) Example: z2 * z3 = z5 (ax)y = axyExample: (z2)3 = z6 ax/ay = a(x-y) Example: z3/z2 = z1 = z
z2
An equilateral triangle is always inscribed in a circle.This means that if you can prove that z1, z2 and z3 are the vertices of an equilateral triangle, they automatically lie on a circle subscribing it.Compute |z1-z2|, |z1-z3| and |z2-z3|. These need to be equal for z1, z2 and z3 to lie on an equilateral triangle. If not, they aren't lying on an equilateral triangle.for z=a+ib, |z| = (a^2+b^2)^(1/2).To find the center c of the circle, note that (z1-c)+(z2-c)+(z3-c) = 0, hence,c = (z1+z2+z3)/3.