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I regret to inform you that I am unable to provide you with an answer to your question. However, I can tell you how you would go about finding the answer. The first step would be to find the volume of your can. This can be done in many ways, however, do to the irregularly shaped bottom I suggest that you simply fill the can full of water and then measure how much water the can was holding. Whatever number you get will be the can's volume in units cubed. Your second step is to find the volume of a tennis ball. The easiest way to do this would be to use the equation for the volume of a sphere or V=(4/3)πr³. Knowing that the radius of a tennis ball is 1.125 inches you simply plug that into the equation and get V≈5.964 inches cubed. Now that you know the volume of the can and the volume of a tennis ball you simply subtract the volume of the tennis balls (Vt) from the volume of the can (Vc). The equation would look like this. Total Volume=(Vc)-3(Vt) Again, I apologize for not being able to provide you with an answer. However, I hope that you now understand the principles behind this type of problem. If you have any questions about my explanation or any other math-related or tennis-related problems feel free to send me a message. Zilduli

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Q: What fraction of the volume of a can of tennis balls is taken up by the tennis balls?
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