217/5 = 43.4With 43 boxes, you can take care of 215 balls. After that, you have a decision to make:You have 2 balls left over. You can either slip them into your pocket and walk away, orput them into Box #44.
There will be a need for 6 boxes because 6*4 = 24
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The problem of placing 10 indistinguishable balls into 8 distinguishable boxes can be solved using the "stars and bars" combinatorial method. The formula for this is given by (\binom{n+k-1}{k-1}), where (n) is the number of balls and (k) is the number of boxes. Here, (n = 10) and (k = 8), so the number of ways is (\binom{10 + 8 - 1}{8 - 1} = \binom{17}{7} = 19448). Thus, there are 19,448 ways to place the balls into the boxes.
560 in the first box 480 in the second box and 160 in the third box
on the side of the box there is a dragon ball with a star. to keep a show trate there will be 7 boxes cause there are 7 dragon balls
There is no international standard size for mail boxes.
If every box contained 11 balls that would account for only 99 balls. The hundredth ball has to be placed in a box already containing 11 balls...
The pigeonhole principle is merely the following observation - "If we are to place N balls into M boxes where N > M, at least one box will contain at least two balls." A generalized version of the pigeonhole principle says that if we place at least nk + 1 balls into n boxes, then at least one box will contain at least k+1 balls. I say "at least" a lot because these numbers are arbitrary and lower bounds.
When you change pen size, the boxes will get bigger or smaller. Balls do not work for this.
soda balls sweat an stripers
I guess you mean "cojones", if that's the case, it means balls, testicles or nuts like when you say "you don't have balls to tell her you're in love with her"